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Mother is left stumped by her seven-year-old daughter's maths homework question (but could...
DAILY MAIL UK ^ | Jan 31, 2018 | Alex Matthews For Mailonline

Posted on 01/31/2018 10:42:17 PM PST by Morgana

FULL TITLE: Mother is left stumped by her seven-year-old daughter's maths homework question (but could YOU work it out?)

A mother was left scratching her head after trying to help her seven-year-old daughter with her maths homework.

Angie Werner was stumped when she tried answer the conundrum and turned to social media to help her out.

The problem asked how many entrants were in a dog show and while at first the answer appeared to be simple - in fact it left many parents completely miffed.

PROBLEM ON LINK

(Excerpt) Read more at dailymail.co.uk ...


TOPICS: Education
KEYWORDS: arth; commoncore; commoncoremath; math
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I can't figure it out
1 posted on 01/31/2018 10:42:18 PM PST by Morgana
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To: metmom

arth ping


2 posted on 01/31/2018 10:42:44 PM PST by Morgana ( Always a bit of truth in dark humor.)
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To: Morgana

Uhhhh.... 36


3 posted on 01/31/2018 10:46:25 PM PST by Vendome (I've Gotta Be Me - https://www.youtube.cwom/watch?v=wH-pk2vZG2M)
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To: Vendome

BTW, that is the dumbest answer ever...


4 posted on 01/31/2018 10:49:38 PM PST by Vendome (I've Gotta Be Me - https://www.youtube.cwom/watch?v=wH-pk2vZG2M)
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To: Vendome

There are 36 more small dogs than large dogs and 49 in total so you need X + (X+36)= 49. By doing basic algebra you get X= 6.5 so there are 42.5 small dogs and 6.5 large dogs. Which are 36 apart and when added equal 49.


5 posted on 01/31/2018 10:51:52 PM PST by LukeL
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There are 49 dogs signed up to compete in the dog show. There are 36 more small dogs than large dogs signed up to compete. How many small dogs are signed up to compete?


6 posted on 01/31/2018 10:52:08 PM PST by jpsb
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To: Morgana

LOL. Weird one for sure. I got the same answer explained in the article.

Total Dogs Large Dogs Small Dogs
49 L 36+L
49=L+(36+L)
49=36+2L
2L=13
13/2=6.5
36+6.5=42.5 dogs...?????!


7 posted on 01/31/2018 10:53:51 PM PST by lefty-lie-spy (Stay metal. For the Horde \m/("_")\m/ - via iPhone from Tokyo.)
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To: Morgana
They should reword the thing, because people who deal in half-dogs get reported to the RSPCA.

x + (x +36) = 49
2x = 13
x=6.5
small dogs = x+36, so 42.5

That's obviously not what they had in mind, but if you can't define a problem correctly nobody can solve it correctly.

8 posted on 01/31/2018 10:55:21 PM PST by Billthedrill
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To: lefty-lie-spy

Yup, this would be a question I would ask to students in 7th to 9th grade. 7th if they were very bright and 9th for an average student. It is basic algebra and requires understanding of fractions and the 4 basic math functions which usually doesn’t happen until 6th grade.


9 posted on 01/31/2018 10:57:07 PM PST by LukeL
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To: lefty-lie-spy
One should never enter 1/2 of a dog into a dog show.

I'm thinking that would be an automatic disqualifier, but that's just me.

10 posted on 01/31/2018 11:00:58 PM PST by SaveFerris (Luke 17:28 ... as it was in the days of Lot; they did eat, they drank, they bought, they sold ......)
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To: SaveFerris

What if the other half identifies as a cat? Then you are in even more trouble.


11 posted on 01/31/2018 11:02:50 PM PST by LukeL
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To: Morgana

42 small dogs
6 big dogs
1 medium dog

or...

42.5 small dogs
6.5 big dogs

or...

the idiot that came up with this problem didn’t know what he was doing.


12 posted on 01/31/2018 11:02:57 PM PST by aquila48
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To: Morgana

x=xmall
y=large

x + y = 49
x - y = 36

Simultaneous equations:

2x + y - y = 49 + 36 = 85

2x = 85

x = 42.5 small dogs


13 posted on 01/31/2018 11:03:25 PM PST by be-baw (still seeking...)
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To: Billthedrill; metmom

42.5

Sooooooooooooooooo how does 1/2 a dog compete in a dog show???


14 posted on 01/31/2018 11:03:58 PM PST by Morgana ( Always a bit of truth in dark humor.)
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To: LukeL

Or if the 1/2 dog starts chasing the 1/2 cat.

It’s almost like Bruce Jenner competing against Chelsea Manning......


15 posted on 01/31/2018 11:05:10 PM PST by SaveFerris (Luke 17:28 ... as it was in the days of Lot; they did eat, they drank, they bought, they sold ......)
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To: LukeL

Not really, there was a whole cartoon series about it.


16 posted on 01/31/2018 11:06:18 PM PST by FredZarguna (And what Rough Beast, its hour come round at last, slouches toward 5th Avenue, to be born?)
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To: Morgana; aquila48
Aquila48 nailed it. 42 small dogs, 6 big dogs, and A CAT!

Dang cats.

17 posted on 01/31/2018 11:06:34 PM PST by Billthedrill
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To: Billthedrill

That’s exactly how I worked it out. The x refers to the big dogs and the x + 36 refers to the small dogs. The problem is that there are 6.5 big dogs and 42.5 small dogs, and since there are two half dogs, they both must be really small...


18 posted on 01/31/2018 11:08:04 PM PST by beejaa
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To: Billthedrill

Aquila48 nailed it. 42 small dogs, 6 big dogs, and A CAT!

And A CAT that self-identified as a medium-sized dog!


19 posted on 01/31/2018 11:08:08 PM PST by SaveFerris (Luke 17:28 ... as it was in the days of Lot; they did eat, they drank, they bought, they sold ......)
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To: LukeL

Algebra is stoopet....


20 posted on 01/31/2018 11:09:49 PM PST by Vendome (I've Gotta Be Me - https://www.youtube.cwom/watch?v=wH-pk2vZG2M)
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