To: lefty-lie-spy
One should never enter 1/2 of a dog into a dog show.
I'm thinking that would be an automatic disqualifier, but that's just me.
10 posted on
01/31/2018 11:00:58 PM PST by
SaveFerris
(Luke 17:28 ... as it was in the days of Lot; they did eat, they drank, they bought, they sold ......)
To: SaveFerris
What if the other half identifies as a cat? Then you are in even more trouble.
11 posted on
01/31/2018 11:02:50 PM PST by
LukeL
To: SaveFerris
Maybe it was a cooking contest?
35 posted on
01/31/2018 11:45:59 PM PST by
21twelve
(http://www.freerepublic.com/focus/f-news/2185147/posts)
To: SaveFerris
One should never enter 1/2 of a dog into a dog show.
well, if it shows well, it's probably a winner.
but seriously, X + (X+36)=49 or large dogs+(large dogs+36)=49 that's wrong
it should be (X+36)=49 or (Xlarge dogs+36small dogs)=49
So X= large dogs = 49-36=13.
How many small dogs are signed up to compete?:
49(all dogs)-13(large dogs)=36(small dogs.)
57 posted on
02/01/2018 2:11:12 AM PST by
867V309
(Lock Her Up)
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