[LukeL]

There are 36 more small dogs than large dogs and 49 in total so you need X + (X+36)= 49. By doing basic algebra you get X= 6.5 so there are 42.5 small dogs and 6.5 large dogs. Which are 36 apart and when added equal 49.

[Vendome]

Algebra is stoopet....

[mdmathis6]

No need for the math. If you have 49 dogs total and 36 OF THOSE 49 DOGS ARE SMALL DOGS, THEN YOU HAVE 36 SMALL DOGS. The last 13 of those 49 in total dogs would be large dogs.
49 total dogs=36 small dogs + 13 large dogs.

I think it was a typo...I think the question meant to ask how many large dogs not how many small dogs. If it was small dogs, the problem become one of those “DUH” questions...like “who was buried in Reagan’s tomb” since the problem states how many small dogs(36) out of 49 total there were already.

[spintreebob]

if you chop a large dog in half does it then become a small.dog?!

Best comment at Daily Mail

[FoxInSocks]

Yep.

[mad_as_he$$]

Easy stuff for every 7 yo kid. /s

[IronJack]

Exactly. It’s pretty simple algebra, although it seems a little advanced for a 7-year-old.

And I’d pay to see those half-dogs.