No need for the math. If you have 49 dogs total and 36 OF THOSE 49 DOGS ARE SMALL DOGS, THEN YOU HAVE 36 SMALL DOGS. The last 13 of those 49 in total dogs would be large dogs.
49 total dogs=36 small dogs + 13 large dogs.
I think it was a typo...I think the question meant to ask how many large dogs not how many small dogs. If it was small dogs, the problem become one of those “DUH” questions...like “who was buried in Reagan’s tomb” since the problem states how many small dogs(36) out of 49 total there were already.
But the question said there were 36 MORE small dogs than large dogs. If there are only 36 small dogs then there are 13 large dogs. 36-13 is only 23.
Agreed- to think that it is an algebraic equation is to think that a second grader would be taught algebra- gotta think like a 2nd grader here. Poorly worded and confusing problem, unless you parse it like a 7 year old would. It should b e worded more like this:
If there are 49 dogs entered in a contest, and there are 36 small dogs entered, how many large dogs are entered? 49-36=??
And we actually pay teachers like these?
I am glad we homeschooled our three- they all a have MA/MS etc and can do math.... I only would have liked to see them all attend Hillsdale or some other non-state funded schools.... Me too.
Education- teaching students how to think, not what to think.
Indoctrination- teaching students what to think, and not how to think....
You and I both think it’s a grammar problem, just form different perspectives. I think yours make more sense, but it’s obviously a typo of some sort.
I had a professor in college who screwed up a Scan-Tron test. Every student in the class got the same four questions wrong.
He got furious when we called him on it and said that he’d re-check it but if he was right, we’d all lose double points. He didn’t know that nearly everyone in the class had the next class together, taught by the dean of the Business Department. He got quite the earful and our tests got corrected.
It happens, deal with it.