Posted on 08/25/2023 8:41:00 PM PDT by Jonty30
If you weigh a cat and a rabbit, their total weight is 10kg. If you weigh a dog and rabbit, their total weight is 20kg. If you weigh the dog and cat, their total weight is 24kg.
How much do all three weight together?
If a steamship weighed 10,000 tons and sailed 5,000 miles
With a cargo large of overshoes and carving knives and files
If the mates were almost six feet high and the bos’n near the same
Would you subtract or multiply to find the captain’s name?
The way the problem is written, each animal was weight twice — and only twice. If the total weight of the three weighings in the three combinations of animals was 54 kg and it doesn’t matter how much each one weighs, just divide 54 by 2 and you get 27 kg.
Since there were 3 animals, 54 - 3 = 51/3 = 17, the weight of the largest, the dog.
Then 24 - 17 = 7, the weight of the cat.
And 10 - 7 = 3, the weight of the rabbit.
So then 17 + 7 + 3 = 27, the total weight of all 3.
Right?
"Simultaneous equations are two or more algebraic equations that share common variables and are solved at the same time (that is, simultaneously)"
But - I'm open to hear your interpretation.
I take it you did not pass algebra?
Let’s assume the weights of the cat, rabbit, and dog are represented by the variables C, R, and D respectively.
From the given information, we can set up a system of equations:
C + R = 10 (Cat and Rabbit weigh 10kg together)
D + R = 20 (Dog and Rabbit weigh 20kg together)
C + D = 24 (Cat and Dog weigh 24kg together)
We can solve this system of equations to find the values of C, R, and D.
From equation 1, we can isolate C: C = 10 - R
From equation 2, we can isolate D: D = 20 - R
Now substitute these expressions for C and D into equation 3:
(10 - R) + (20 - R) = 24
Combine like terms:
30 - 2R = 24
Subtract 30 from both sides:
-2R = -6
Divide by -2:
R = 3
Now that we have the weight of the rabbit (R = 3 kg), we can substitute it back into equations 1 and 2 to find the weights of the cat and the dog:
From equation 1: C = 10 - R = 10 - 3 = 7 kg
From equation 2: D = 20 - R = 20 - 3 = 17 kg
So, the weights of the cat, rabbit, and dog are C = 7 kg, R = 3 kg, and D = 17 kg.
Finally, to find the total weight of all three animals together:
Total weight = C + R + D = 7 + 3 + 17 = 27 kg
Therefore, the total weight of the cat, rabbit, and dog together is 27 kg.
The way the problem is written, each animal was weight twice — and only twice. If the total weight of the three weighings in the three combinations of animals was 54 kg and it doesn’t matter how much each one weighs, just divide 54 by 2 and you get 27 kg.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
LOL! Demonstrated the importance of reading comprehension didn’t it?
Easy.
2C + 2D + 2R = 54
Divide each side by 2:
C + D + R = 27.
You too, eh?
Is your fourth grader doing new math or something?
Cats can increase or decrease their weight at will. A cat will turn its weight down to almost nothing when it floats up onto the kitchen counter where it knows it's not allowed to be, or it will turn its weight up to the equivalent of a Shetland pony when it stomps across you in the middle of the night.
They can also put out powerful sleep rays, especially when purring.
Kids have word problems this week? Ha ha.
You, sir, win this thread!
(Spoken in my best llama song voice)
Nicely done.
I sucked at algebra….
Thanks. You can see the years of “show your work” drilled into my head.
This works because each variable is used twice. I used this same trick in a spreadsheet to find the grand total of a column which contained subtotals for each group of numbers.
I have not looked at any replies to your post.
C + R = 10
D + R = 20
The dog weighs 10 pounds more than the cat.
D = C + 10
C + D = 24
C + (C + 10) = 24
2C = 14
C = 7
R = 10 − 7 = 3
D = C + 10 = 17
Total weight = C + D + R = 27kg
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