Posted on 11/03/2016 7:04:30 PM PDT by workerbee
A San Antonio Thai restaurant, Yaya, will let you use its Wi-Fi for free-- but only if you can solve this insanely complex math equation.
Reddit user “Joshua_Glock” posted a picture of the restaurant’s handwritten Wi-Fi equation this past weekend, but no one has been able to connect to the network yet, First We Feast reported.
(Excerpt) Read more at foxnews.com ...
They should require something like this to get welfare payments and food stamps. Of course, a little bit easier formula to solve. A lot easier. Maybe 4th grade level. That will cut the welfare rolls in half. Or way more.
Looks like the upper half of a binomial distribution, in which case the answer is 1/2. Maybe the password is one-half, or some variant thereof. But, if that’s the case, the term written as (m/n) after the summation sign should be the binomial coefficient, which is normally written without the division sign, just as the two numbers over each other inside the parentheses.
But, I’m a bit rusty, to tell the truth.
(Muttering darkly) One second. Only math problem I ever got right in my life...one second...(sulking)...
Cumulative binomial distribution function.
https://en.wikipedia.org/wiki/Binomial_distribution#Cumulative_distribution_function
Not “complex”
This should be a requirement for voting!
Scientific calculator solves this in about a minute,, and that’s allowing for input by somebody that knows how to use one.
Yeah, okay... Well.... I know how to spell “customers”!!!
;-)
“And yes, the answer is 42.”
Which is always my fave response.....’but...
I did think I saw that they wanted a probability.
Which methinks limits the answer range from 0 to 1.
(0 being the IQ of the MSM, of course.)
FRiend, calculus is so far in the rear-view mirror, I'd need a telescope to make out the sigma.
Or you could just put in the router IP address, type in Admin/Admin and change the password on them.
Very close!
Actually, 42.27
On second thought, it’s a biased binomial distribution, since the probabilities are .25 and .75. So the probability of occurences greater than N/2 is less than 1/2. Have to think about it a bit more.
P(m >= N/2) = (SUM from m=N/2 to N)[(N/m)(0.25)^m(0.75)^(N-m)]
I looked at the equation. Don’t know the answer. Sadly, I cannot solve the equation like my father could. Isaac Newton discovered calculus and gave physics a huge boost after Copernicus, Kepler and then Galileo. Leibniz also discovered calculus and his writings about the Lord are pure brilliance. He was a special philosopher. What have I discovered? How to make an espresso, thanks to Youtube.
Ummm...I can spel calculus...
I’m not sure where my slide rule is.
Thinking really hard, I might still remember what the integral sign is for...
P(m>=(n/2)) is a function. M can vary from anything greater than or equal to n/2 (except zero), and from what I can see, n can vary from negative to positive infinity.
For example, if n=8, then m can be any value >= 4 (let's say 4). The equation becomes P(4) = (8/4)*(.25^4)*(.75^(8-4)). Simplifying, P(4) = 2*.003125*.31640625. Again, P(4) =.0019775390625.
But since this is a summation (the "sigma") from m-n/2 to n, we would need to calculate another P(m), using another m and n. Then we would need to calculate another and another and another, and add each result to the previous until we approached a real number. I have no idea what that number would be, but you could plug the equation into a spreadsheet and calculate P(m) using different values of n and m and see if the number looks like anything significant.
Just a guess, but I'm betting it approaches 1 for all real values of n and m.
The short version is: wifi is 7 bucks an hour
A greater than or equal to statement is a clue, not a variable. This “math problem” is a farce.
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