What word in the English language is made up of only two letters, each used three times?
Posted on 08/29/2006 9:17:38 AM PDT by taxcontrol
Wouldnt want to do it in MASM.... that is for sure.
Try it in FORTRAN...c'monnnnn, I dare ya!
FORTRAN is easy.
COBOL is easy.
Assembler is HARD! Well not all that hard but a huge pain in the neck to code in .
I wonder if anyone here can do it in original BASIC...
Why not just code it in malbolge?
heh
http://www.lscheffer.com/malbolge.shtml
God, I love those knives.
Or better yet... Brainf***
http://www.muppetlabs.com/~breadbox/bf/
yes it is a programming language.
bttt
I've forced many a cork into the bottle.
But not to remove a coin I must confess . . .
As have I (hic).
Here's another one:
How would you rearrange the letters in the words "new door" to make one word? Please note, there is only one correct answer.
I do too I have the Wolfgang Puck signiture set
http://www.hsn.com/cnt/prod/default.aspx?pfid=542317&club_id=542317&sz=5&sf=QC0051&rdr=1&cm_mmc=ShoppingEngine*BizRate*qc0051*542317
You did rearrange them unless I missed something.
What word in the English language is made up of only two letters, each used three times?
Deeded
(sigh)
Are you that good or googling likethatcheatinglittlemidget? ;-)
Honestly I saw through the first one and remembered the second.
I'm not that clever.
Looks about right.
What is the longest word in the dictionary?
Wait for it
Answer :
Smiles
(there is a mile between the two S's)
WOOPWOOPWOOPWOOP
I think you need to look at what each cell on the diagonal also influences. If the top right is a one, then none of the top row or the far right column can have a 1, nor can the top box. Think of Sudoku as being nine boxes, each of those with nine cells.
The diagonals will occupy three cells in each of box 1, 3, 7 and 9, 5 cells in the middle box and no cells in boxes 2, 4, 6, and 8.
The middle box will have five unique numbers on the diagonals. None of the numbers can be the same, because a sudoku box can't have a duplicate.
In the four corner boxes, we have three numbers each. Each box cannot have a duplicate number. Furthermore, each cell in the corner box is on the same column as a cell in another corner box and a row in another corner box.
There are not enough constraints to force a duplicate in the diagonal. I don't know how to express this in a mathematical proof, but it if you assign each cell a variable, and cell 1 <> cell 2 <> cell 3 maybe you could approach it that way.
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