And now something completely different. How NERDY are You?

Nerd Test ^ | 2-19-06

[Indy Pendance]

Have fun! I'm just a low-ranked nerd.

[Alamo-Girl]

Wow! Way to go ... another INFJ!

[Indy Pendance]

I wonder if it's rigged, or do more of us tend to take these types of polls?

[Alamo-Girl]

Or perhaps INFJ's are intense in their politics and thus apt to frequent Free Republic?

[Indy Pendance]

That's a thought too. It's interesting. In 1979, I did a manual poll, pre-everyday-computer-user days, and ended up with the same results.

[Alamo-Girl]

Indeed. Birds of a feather and all that...

[BookmanTheJanitor]

I really don't despise nerds....honest :o).

[Indy Pendance]

LOL!

[Washi]

But, I knew how to imbed the hyperlink test score without having to cut and paste, so I may have to add a couple of points.

[Indy Pendance]

I know, My hubby built my computer, but I can do it too.

[John O]

Now, Ron took the test when he was standing over my shoulder, and he only scored a 65.

I think he's bluffing.

I agree. There's no way I'm a bigger nerd than he is (as defined by this test) I bet he programs in his sleep even!

[John O]

That is too precious!!

[John O]

in the test on 162 I'm an INTJ

[John O]

for interest:

I 67

N 25

T 62

J 67

(A-G, just in case you're still collecting data)

[6ppc]

71st percentile - Mid-Level Nerd

[Professional Engineer]

That is too precious!!

tHIS ONE IS PRETTY GOOD TOO!

[John O]

I agree, beautiful child. (Not as cute as mine was at that age but still beautiful.)

I have to confess though that my math skills aren't what they once were. What's the english translation of the equation?

[Alamo-Girl]

Hi John O! Thanks for letting me know - and yes, I am collecting the results.

[Professional Engineer]

Man, yer gonna make me think here.

And God said...

ò E.dA = q/e₀

ò B.dA = 0 

ò E.ds = -d/dt(ò B.dA) 

ò B.ds = m ₀ò j.dA,

...and there was light.

---------------------------------

In sorta plain Engrish.

And God said...

The sum (integral) of an electric field with respect to an area is equal to the charge divided by a universal constant.

The sum of a magnetic field with respect to an area is equal to zero.

The sum of an electric field with respect to a segment is equal to the negative change (derivative) with respect to time of the sum of a magnetic field with respect to an area.

The sum of a magnetic field with respect to a segment is equal to some other universal constant multiplied by the sum of j (where the heck is my physics book) with respect to an area.

...and there was light.

[John O]

Man, yer gonna make me think here.

I know it's painful but you can do it! :^) Thanks for the info.

[b4its2late]

Don't click it, cause it'll only take you to photobucket.com but here's my score.......