point of impact was 8:00... splatter or shock wave broke the baloon
Posted on 08/05/2014 7:08:14 PM PDT by kjam22
Here's a guy who pops a balloon from 1000 yards with a 9mm. Fact or fiction?
It is a heck of a trick shot.... maybe not as good as in the old westerns when they rode out of town at a gallop and shot the telegraph wires in to from the back of the horse.... Now that was trick shooting :)
Are you sure?
Bullets all fall at the same speed but the faster they go the farther they go before hitting the ground. If you dropped a bullet from your hand at the same time you fired the gun (if the gun was level) they would both hit the ground at the same time. The bullet starts falling the instant it leaves the gun, it is just a race to see how far it can go before falling all the way down.
My personal protection rounds of 9mm only have 125gr and that is a little more than my practice rounds at about 115. I would hate to be standing behind someone if they are shot with a 147gr load, it would likely go right through them, but then you wouldn't have to shoot twice. The report would scare anybody away.
It does begin to drop as soon as it leaves the muzzle, when compared to the mathematical line that includes the axis of the barrel and which extends out from the muzzle to infinity.
If the muzzle is aimed at a point five degrees above the horizon, the bullet starts to fall below that line the instant it leaves the muzzle. The bullet is still climbing with respect to a horizontal, but it is falling with respect to the muzzle axis.
When he said he aimed at a point 75 yards above the target, that does not mean that the round ever got 75 yards above the target, not even close.
Wish I could see 1000 yards, let alone hit a target.
Yeah.... that’s me.
point of impact was 8:00... splatter or shock wave broke the baloon
I would say that the squirrel was at a 60 degree angle when it bit...
To quote the NRA show on the Outdoor Channel, that’s an “Impossible Shot.”
lol
Is there an echo in this room?
” If you dropped a bullet from your hand at the same time you fired the gun (if the gun was level) they would both hit the ground at the same time”
Not a mechanical engineer or a physicist, but your statement would only be true in controlled conditions.
Depending on the round, for example, they can tend to gain some altitude as they fly, and as the velocity slows they drop. The air has a lot of effect.
Now if you did it in a vacuum, your assertion would be more accurate.
It is a heck of a trick shot.... maybe not as good as in the old westerns when they rode out of town at a gallop and shot the telegraph wires in to from the back of the horse.... Now that was trick shooting :)
-=0=-
Or splitting a slug on the edge of an axe to break two (one each side of the blade)eggs.....some claim to have witnessed same.
Sorry, had to drive home before I tackled the next step.
Check.
If we add in the angle.
horizontal terms
Sin(ang)=vert/fps. cos(ang)=dist/fps
So. Fps*Cos(ang)= dist (ft/sec)
Time= distance/dist = distance/(fps)*Cos(ang)
Vertical terms
Initial vertical velocity (fps) = fps*Sin(ang)
Less acceleration due to gravity = a = -9.8 m/s
Velocity = integral ( a dt) from t to to = at + Vi. = fps*Sin(ang) - 9.8 m/s * t
Then height is. Integral of above = Vi t - 9.8/2 * t^2. = fps*Sin(ang) - 9.8/2 * t
It wouldn’t be going 1000 fps the whole way. So it would be quite a bit more than 3 seconds. And quite a bit more than 30 meters.
Assumed target was at same height as gun.
So an angle of about 0.84 is needed.
Watch the video. Three seconds is good for our purposes. 1:03 for the shot
1:06 for the popping
My first choice for a wingman in a foxhole.
Disclaimer: Opinions posted on Free Republic are those of the individual posters and do not necessarily represent the opinion of Free Republic or its management. All materials posted herein are protected by copyright law and the exemption for fair use of copyrighted works.