It's all differential equations these days...
...maybe you need a refresher course?
Posted on 12/12/2013 8:47:50 PM PST by Innovative
There are also traditional word problems. Twitchy has found a word problem that may be the most egregiously awful math problem the Common Core has produced yet.
Take a look:
15. Juanita wants to give bags of stickers to her friends. She wants to give the same number of stickers to each friend. She's not sure if she needs 4 bags or 6 bags of stickers. How many stickers could she buy so there are no stickers left over?
(Excerpt) Read more at dailycaller.com ...
That doesn’t follow at all.
number of friends minimum bags
1 4
2 4
3 6
4 4
6 6
Hmm...if she is able to buy 4 bags or 6 bags, the store must sell them in packs of 2. So if she has only one or two friends, she could buy 2 bags of stickers and be done.
So she must have either 3, 4, or 6 friends.
I’m inclined to eliminate 6 friends too. If she had 6 friends, she wouldn’t consider buying 4 bags of stickers.
By the same reasoning, if she had 4 friends, she would know to buy 4 bags of stickers.
I’m guessing that she has 3 friends, and the answer they’re looking for is 6 bags. But as you see this takes a couple of huge assumptions.
Do you really think this was a “least common multiple” question?
I really can’t see lefties actually valuing the ability to do that.
3 Friends, 4 bags does not work even if the stickers are sold two to a bag.
While Mythbusters proved you can polish a turd, nobody can polish this one.
Another possible answer....Juanita should give each friend one sticker and keep the rest for herself.
The answer the respondent writes can then be sent to the mental health review board for evaluation.
Geeze, you guys are just SOOOO 20th century!
The answer is “farther.”
Only homophobe lines self identify as straight!
Oh, and they’re racist against gays!!
First of all she needs to set up an exchange. Then she needs to outlaw all her friends stickers. Then she makes a deal with the sticker company to sell her stickers at 4 times the old price but you don’t get any stickers at all until you giver her a deductible of 6000 bucks. For those with no money she will have to add a surcharge to those with money so she can dole out a sticker here and there to the “needy”.
In current terminology, the task is to:
Make X the subject of the number sentence.
Subjects and sentences belong in English class, not math class.
The key is “It doesn’t matter what they answer - they will move on to the next grade regardless”.
It's all differential equations these days...
...maybe you need a refresher course?
5th grade. It is straight out of the State of California approved/mandated math workbook.
AN answer is six bags ... 4 cannot be divided by an odd number (3), so if she has three friends, having four bags will not work out without leftovers.
Its not a hoax. That was actual homework that my daughter was assigned.
I agree.
They also blew away any advantage of using metric distance measurements by breaking meters into sixths and eighths.
“the same number of stickers “
It’s the same number of stickers, not same number of bags, of course we don’t know how many stickers are in a bag..
When teaching Chess to kids I used that problem and the kids had to solve it in their heads then tell me how they did it. The key is that the farmer can come back empty to the original side ... take fox over, go back get grain, take fox back and pick up goose, take goose over and pick up grain and bring back, then pick up fox and take over and bring back grain, then return empty and bring goose over to where grain and fox are waiting ... except the goose would wander off when the grain is gone anyway.
Goose over return for the fox, take fox over return with the goose, take grain over return empty and take goose to the waiting fox and grain
Your problem is actually valid.
x=10-y
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