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Light Can Twist as Well as Spin
NASA -- Astronomy Picture of the Day ^ | 11-19-03 | apod

Posted on 11/19/2003 3:30:55 AM PST by Boot Hill


Explanation:   Light is more complicated than we thought. When astronomers measure light, they are usually concerned with its direction, energy, and spin polarization (sometimes). Recently, however, it has been more broadly realized that photons can also have orbital angular momentum (OAM), an attribute classically analogous to the Earth orbiting the Sun as well as spinning on its axis. Pictured above, the wave-front of a photon with OAM is shown to be twisted, in contrast to the flat plane of zero OAM light. Light with OAM might be used to increase the information content of communication or to discern specific types of astronomical sources. Passing through a common lens, light without OAM focuses to a point, whereas light with OAM focuses to a ring. Most light bouncing around the cosmos, however, is expected to have so little (or zero) OAM that the created ring is too small to measure. Even given other promising methods for measurement, exploiting OAM for astronomical discovery might be as much an issue of observational practicality as theoretical possibility.


TOPICS: Extended News; Miscellaneous; Technical
KEYWORDS: light; optics
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To: BigLittle
BWa hahahhaah, pretty cool.
21 posted on 11/19/2003 9:18:49 AM PST by richtig_faust
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To: Amelia
I think you'll like this one. ;-)
22 posted on 11/19/2003 9:19:45 AM PST by Scenic Sounds (Hoy, no tengo ningĂșn mensaje a compartir.)
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To: Buckhead
Does this have any implications for the observed red shift upon which the Big Bang theory rests?


No, the red shift is based on a doppler shift (frequency shift) it has nothing to do with this.
23 posted on 11/19/2003 9:20:03 AM PST by richtig_faust
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To: Boot Hill
Like this?


24 posted on 11/19/2003 9:27:24 AM PST by <1/1,000,000th%
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To: Boot Hill
Warp Nine now, Mr. Data!
25 posted on 11/19/2003 9:29:21 AM PST by AxelPaulsenJr (Excellence In Posting Since 1999)
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To: edwin hubble
Thanks for the ping.
26 posted on 11/19/2003 9:32:44 AM PST by PatrickHenry (Felix, qui potuit rerum cognoscere causas.)
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To: RadioAstronomer; All
I can't get a handle on this. If we observe light with OAM, what are we supposed to conclude about it's origin? What does this data tell us? If this is going to be an astronomical tool, what do we use it for? (In case all of this is obvious, then break it to me gently.)
27 posted on 11/19/2003 10:45:06 AM PST by PatrickHenry (Felix, qui potuit rerum cognoscere causas.)
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To: RightWhale
Thanks for the promo, RightWhale! :-)
28 posted on 11/19/2003 1:02:53 PM PST by petuniasevan (Kirk: Oh no! Ensign Pillsbury! Bones: He's bread Jim!)
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To: Boot Hill
Light Can Twist as Well as Spin

Holy Foot Candles Batman - Light has been taken over by the DemoncRATS!

29 posted on 11/19/2003 1:09:54 PM PST by N. Theknow (Be a glowworm, a glowworm's never glum, cuz how can you be grumpy when the sun shines out your bum.)
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To: richtig_faust
richtig_faust sez:   "I thought we knew that back in Maxwell's time."

Yes, it is amazing how all of man's discoveries about EM wave phenomena comport so exactly with Maxwell's equations.

--Boot

30 posted on 11/19/2003 1:49:57 PM PST by Boot Hill
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To: richtig_faust; Buckhead
richtig_faust sez:   "No, the red shift is based on a doppler shift (frequency shift) it has nothing to do with this."

You know, I almost answered Buckhead that way, but then I realized I was responding less to his specific question, than to where I sensed he seemed to be heading with his query (a short lifetime universe).

While it is true that the current state of science regarding the red shift is that it is due to Doppler shift, nonetheless, one would be taking an imprudent step to translate that "understanding" to a non-scientific limit of "proven and irrefutable".

Since the phenomenon described in the thread article is so new and there is so little understanding of how it would be created in nature, or how an existing "normal" light beam could be "twisted" or how twisted light could be detected, distinguished and observed, it might be more prudent to be a bit more circumspect in regards to such answers.

For instance, in #13 above, I present one possible scenario with "twisted" light that could account for an apparent lowering of its frequency like occurs with red shift. Could this account for the observed astronomical red shift? It's possible, but while I don't think so, I also believe that it is still too early just to give a blanket "No" to the question.

--Boot

31 posted on 11/19/2003 2:51:19 PM PST by Boot Hill
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P L A C E M A R K E R
32 posted on 11/19/2003 6:42:00 PM PST by PatrickHenry (Felix, qui potuit rerum cognoscere causas.)
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To: edwin hubble
Thanks for the ping :-)
33 posted on 11/19/2003 8:01:06 PM PST by RadioAstronomer
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To: PatrickHenry
I can't get a handle on this. If we observe light with OAM, what are we supposed to conclude about it's origin? What does this data tell us?

I need to look at this closer.

34 posted on 11/19/2003 8:52:50 PM PST by RadioAstronomer
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To: maxwell; Physicist; VadeRetro; RightWhale
ping
35 posted on 11/19/2003 8:54:26 PM PST by Chancellor Palpatine
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To: ovrtaxt
Hey! Whadda ya think yer doin' sneakin' around in my backyard taken pitchers. There oughta be a law ...
36 posted on 11/19/2003 8:58:39 PM PST by MHGinTN (If you can read this, you've had life support from someone. Promote life support for others.)
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To: Boot Hill
Except for the fact that color is based on FREUQUENCY not momentum or force.
37 posted on 11/20/2003 6:20:46 AM PST by richtig_faust
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To: richtig_faust
richtig_faust says:   "Except for the fact that color is based on FREUQUENCY not momentum ..."

Your statement is incorrect. Frequency is intimately connected to the photon's momemtum because when a photon looses momentum, the result is a loss of energy. And the consequence of a photon losing energy, is a decrease in frequency, i.e., a red shift. See below.

momentum:
p = m*v

energy of a photon:
E = h*f = mc2
      (where h = Planck's constant)

and by combining eq. 1 and eq. 2, we get the momemtum of a photon:
p = h*f/c
      (where c = speed of light)

From eq. 3 it can be seen that if the photon's momentum (p) decreases, the frequency (f) must also decrease.

--Boot Hill

38 posted on 11/20/2003 9:37:02 AM PST by Boot Hill
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To: Boot Hill
I don't get any of this, but I did stay at a Holiday Inn Express last night.
39 posted on 11/20/2003 9:39:13 AM PST by Principled
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To: Boot Hill
Anyone who lived through the disco era could have told them that.
40 posted on 11/20/2003 9:44:21 AM PST by rogers21774 (The guilty taketh the truth to be hard, for it cutteth them to the very center.)
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