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To: Reverend Wright

The Savannah loss happened on February 5, 1958, a US Air Force B-47 bomber collided with an F-86 fighter jet near Savannah, Georgia, resulting in the loss of a 7,600-pound Mark 15 nuclear bomb. To safely land, the pilot jettisoned the weapon into the Wassaw Sound near Tybee Island. It dug into many feet of silt and has not been located. It was not armed. The Air Force officially said the bomb was equipped with a simulated 150-pound lead core, not the plutonium needed for a nuclear explosion, making it incapable of a nuclear blast. If it had been armed, they would have looked for the thing until it was found. And even if it was, it is very difficult to explode a nuclear device. It doesn’t work like lighting a fuse on dynamite like in the TV westerns.

wy69


7 posted on 04/29/2026 10:40:01 PM PDT by whitney69 (uestiuetion and interpret the answer.)
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To: whitney69

The Goldsboro bomb #2 part of it was estimated at 180 feet deep, 100+ feet below the water table, exact location unknown. So it is still there.

https://en.wikipedia.org/wiki/1961_Goldsboro_B-52_crash


9 posted on 04/29/2026 10:53:31 PM PDT by Reverend Wright ( Anschluss now !)
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