Possible radiation from thin film metal surface with anomalous excess heat: Can we observe hot spots or Bremsstrahlung?

Research Center for Electron Photon Science, Tohoku University, Japan ^ | June 2020 | J. Kasagi 1 , T. Itoh 1,2 and Y. Iwamura 1

[Kevmo]

Kasagi: Possible radiation from thin film metal surface with anomalous excess heat: Can we observe hot spots or Bremsstrahlung?

J. Kasagi 1 , T. Itoh 1,2 and Y. Iwamura 1

1 Research Center for Electron Photon Science, Tohoku University, Japan 2 Clean Planet Inc., Japan

In the ICCF21, we reported that no radiations with photon energy higher than 50 keV were observed associated with the excess heat generation in NiCuZr-H2 system. This means that the reaction does not produce energetic particles that undergo a secondary nuclear reaction with the material in the sample, nor does it produce radioactive nuclei. Then a question is ‘How is locally generated energy of above MeV transferred to the thermal energy of the sample?’

Here, we consider a naive situation in which the energy (Q) generated by the reaction is given to an extremely small region and is instantaneously transferred to kinetic energies of all conduction electrons there (the number of electrons is Ne). These electrons lose their energy by ionizing and exciting the substance during traveling a distance of the range (R), which may be a radius of a sphere of the hot spot. Then, the temperature of the hot spot rises by T = Q/MC (M: mass of the hot spot, C: specific heat capacity).

For a thin Ni foil with Q = 1 MeV, a hot spot is formed only for the case of 500 < Ne <1000; corresponding radius 38 > R > 16 nm and temperature 145 < T < 2150 K. When the excess heat is 1 W, hot spots are repeatedly generated in the sample at a rate of 6.3×1012 / sec.

Although very rough, 10-3 to 10-4 of the total number of Ni are included in a hot spot portion. Thermal radiation should be observed from the hot spot on the film surface. An energy spectrum expected for photon emissions from the thin film surface is shown in Figure.

Present are hot spots with T = 2000 K (red dashed-dotted line) and 300 K (red dashed line) at the ratio of (hot spot area) / (sample surface area) = 10−6 on the surface of a film at T= 700K (blue solid line).

One can say that if the temperature of the hot spot is high enough, visible light spectroscopy will reveal the presence of hot spots. When Ne decreases (electron energy increases), Bremsstrahlung emitted by electrons might be visible.

Figure also shows the expected Bremsstrahlung emission by 33 keV electrons generated when Ne = 30 (black dashed line). In the visible light region, the spectrum is not affected by the Bremsstrahlung at all. Thus, a measurement of keV region or higher is essential in order to clarify the presence of the Bremsstrahlung.

We have just begun to search for radiation associated with anomalous excess heat for a wide range of photon energies from eV (visible light) to keV (X ray). Radiation from metal film surface is a prime target.

[Kevmo]

I'm afraid I don't understand what Bremsstrahlung is, I'm gonna have to read up on it.

[Kevmo]

for the cold fusion ping list

[rlmorel]

Bremsstrahlung is scattered radiation that occurs when metal objects are subjected to gamma radiation.

From my old Nuclear Medicine days...:)

I saw the word and it piqued my interest...it can cause problems with imaging.

[Red Badger]

Basically, ‘heatsinking’...................

[rlmorel]

Basically, scattered radiation. Been a long time since I saw the word in a public forum!

[Kevmo]

Bremsstrahlung
From Wikipedia, the free encyclopedia
https://en.wikipedia.org/wiki/Bremsstrahlung

Bremsstrahlung /ˈbrɛmʃtrɑːləŋ/[1] (German pronunciation: [ˈbʁɛms.ʃtʁaːlʊŋ] (About this soundlisten)), from bremsen “to brake” and Strahlung “radiation”; i.e., “braking radiation” or “deceleration radiation”, is electromagnetic radiation produced by the deceleration of a charged particle when deflected by another charged particle, typically an electron by an atomic nucleus.

The moving particle loses kinetic energy, which is converted into radiation (i.e., photons), thus satisfying the law of conservation of energy. The term is also used to refer to the process of producing the radiation.

Bremsstrahlung has a continuous spectrum, which becomes more intense and whose peak intensity shifts toward higher frequencies as the change of the energy of the decelerated particles increases.

Broadly speaking, bremsstrahlung or braking radiation is any radiation produced due to the deceleration (negative acceleration) of a charged particle, which includes synchrotron radiation (i.e. photon emission by a relativistic particle), cyclotron radiation (i.e. photon emission by a non-relativistic particle), and the emission of electrons and positrons during beta decay. However, the term is frequently used in the more narrow sense of radiation from electrons (from whatever source) slowing in matter.

Bremsstrahlung emitted from plasma is sometimes referred to as free–free radiation. This refers to the fact that the radiation in this case is created by electrons that are free (i.e., not in an atomic or molecular bound state) before, and remain free after, the emission of a photon. In the same parlance, bound–bound radiation refers to discrete spectral lines (an electron “jumps” between two bound states), while free–bound one—to the radiative combination process, in which a free electron recombines with an ion.

[PGR88]

Bremsstrahlung is one of those particular German words that describes the feeling you get when you begin talking to a beautiful woman, but then your mother suddenly appears and tells you to come home immediately and clean your room and the woman laughs at you and goes off with the captain of the football team from Romania.

[PGR88]

As in

Verdammt Mutter du hast mich sehr bremsstrahlung gemacht

[Sirius Lee]

“Sitting on a park bench...”

[beethovenfan]

It’s translated “braking radiation”. (I like to say it - “bremsstrahlung”!!)

[rfp1234]

The intensity, I, of the Bremsstrahlung X-rays at any energy E in the spectrum is given by Kramers’ Law

I ≈ ip.Z(Eo-E)/E

where ip is the electron probe current and Z is the mean atomic number.

The intensity is zero where E = Eo (the Duane-Hunt limit) but approaches infinity (∞) as E approaches zero.

Note that according to Kramers’ Law, the intensity of the Bremsstrahlung X-rays is proportional to Z, the mean atomic number of the specimen. This means that heavier materials like Pb or Au will produce more Bremsstrahlung X-rays than samples made from lighter elements such as C or Al.

(Source: https://myscope.training/legacy/analysis/eds/xraygeneration/bremsstrahlung/#detail)

[TexasGator]

First time I have heard of CIF, Cavitatation Induced Fusion.

Should I shield my pool pump?

[algore]

“Possible radiation from thin film metal surface with anomalous excess heat”

Possible herd immunity from leaky human covid injections with anomalous excess variants

or something possibly

[rlmorel]

LOL! It reminds me of that scene from the Raiders of The Lost Ark movie where Indiana Jones and his father (Sean Connery) are tied to a chair, and she lays a slurpy lip lock on him and says:

"That’s how Austrians say goodbye."

Then the evil Nazi appears in his field of view:

Indiana Jones says: "...Ooooh... I like the Austrian way better."

[PapaBear3625]

Bremsstrahlung is scattered radiation that occurs when metal objects are subjected to gamma radiation.

Correction (from wiki):

"electromagnetic radiation produced by the deceleration of a charged particle when deflected by another charged particle, typically an electron by an atomic nucleus. The moving particle loses kinetic energy, which is converted into radiation (i.e., photons), thus satisfying the law of conservation of energy. The term is also used to refer to the process of producing the radiation. Bremsstrahlung has a continuous spectrum, which becomes more intense and whose peak intensity shifts toward higher frequencies as the change of the energy of the decelerated particles increases."

An example is how X-rays are generated by electrons being shot at a metal plate.

[Vaquero]

It’s like black lung or lumber lung. Only different

[taxcontrol]

I wonder if there is a yet unidentified action. I am not a chemist or even high school physics teacher, so I have no background to comment, but I will ask the following.

What if the materials form some type of energy antenna? Perhaps turn magnetic fields into heat? Kind of like a thermocouple but works on a different (non nuclear) law of physics? Would there be a way to structure that as a lab experiment?

Just speculation on my part.

[rlmorel]

Of course, I am looking at it from the perspective of medical imaging, which is likely very a very narrow focus...

I had to laugh at myself, though...when I saw it, my brain silently shouted “Bremsstrahlung!”

Heh, I think I knocked a few neurons out of their comfortable retirement chairs!

[Wonder Warthog]

The Cold Fusion/LENR Ping List

http://www.freerepublic.com/tag/coldfusion/index?tab=articles

Keywords: ColdFusion; LENR; lanr; CMNS
chat—science

—

http://lenr-canr.org/

Vortex-L
http://tinyurl.com/pxtqx3y

Best book to get started on this subject:
EXCESS HEAT
Why Cold Fusion Research Prevailed by Charles Beaudette

https://www.abebooks.com/9780967854809/Excess-Heat-Why-Cold-Fusion-0967854806/plp

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[Kevmo]

The observation has been that deuterium or hydrogen interact with some metals to produce heat. There are known chemical pathways to produce heat, but what has been observed is a level of heat well above what can be expected with ordinary chemistry. I like to think of it as a super-duper resonating chemistry.

When there’s radiation as high as gamma rays, it is a proof that this thing is nuclear.