Okay, so here we are with 9th grade Algebra again. Can anyone give us step by step instructions on this?
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To: netmilsmom
2 posted on
03/16/2010 10:30:41 AM PDT by
1rudeboy
To: StarCMC
4 posted on
03/16/2010 10:33:14 AM PDT by
netmilsmom
(I am Ilk)
To: netmilsmom
5 posted on
03/16/2010 10:33:21 AM PDT by
Perdogg
("Is that a bomb in your pants, or are you excited to come to America?")
To: netmilsmom
6 posted on
03/16/2010 10:33:37 AM PDT by
andy58-in-nh
(America does not need to be organized: it needs to be liberated.)
To: netmilsmom
Off the top of my head, 15 & 50.
How to do it algebraically - no clue! Sorry.
7 posted on
03/16/2010 10:34:02 AM PDT by
brityank
(The more I learn about the Constitution, the more I realise this Government is UNconstitutional !! Â)
To: netmilsmom
You take a guess. hmmmm . . . about a 50 and 15? let’s try that:
50 divided by 15 is 3 with a remainder of 5. Who needs algebra when you can get is right by guessing!
8 posted on
03/16/2010 10:34:32 AM PDT by
ZGuy
To: netmilsmom
A + B = 65
B / A = 3, remainder of 5
(3 x A) + 5 = B
substituting this in the first equasion
A + (3 x A) + 5 = 65
4 x A = 60
A = 15, B = 65 - 15 = 50
9 posted on
03/16/2010 10:34:39 AM PDT by
blowfish
To: netmilsmom
"Okay, so here we are with 9th grade Algebra again. Can anyone give us step by step instructions on this?" My math teacher told us the most important thing to remember in Algebra is:
"X" always equals one... unless it doesn't...
then it equals something else...
11 posted on
03/16/2010 10:35:40 AM PDT by
Mad Dawgg
(If you're going to deny my 1st Amendment rights then I must proceed to the next one...)
To: netmilsmom
First equation: a + b = 65
Next equation: a = 3b + 5
If you substitute the second equation into the first for a, then 4b + 5 = 65 so b = 15 and a = 50.
To: netmilsmom
x + y = 65
x = 3y + 5 so x -3y = 5
subtract one expression from the other (remember minus a negative = plus)
x + y = 65
- x - 3y = 5
__________________
(0x) +4y = 60
y = 15
x = 50
check 1:
x + y = 65
50 + 15 = 65
check 2:
x = 3y + 5
50 = (3 * 15) + 5
50 = 45 + 5
50 - 50
17 posted on
03/16/2010 10:38:55 AM PDT by
Mr. K
(This administration IS WEARING OUT MY CAPSLOCK KEY!)
To: netmilsmom
x + y = 65
x = 3y + 5
==> (3y +5) + y = 65 (substituting second into first)
4y + 5 = 65
4y = 60
y = 60 / 4 = 15
x = 3y + 5 = 50
To: netmilsmom
x + y = 65
x = 3y + 5
solve
To: netmilsmom
3x+5+x=65
4x=65-5
4x=60
x=15
x+y=65
15+y=65
y=65-15
y=50
22 posted on
03/16/2010 10:39:12 AM PDT by
OrioleFan
(Republicans believe every day is the 4th of July, democrats believe every day is April 15)
To: netmilsmom
15 and 50
X + Y = 65
Y = 3X + 5
Substitute for Y = X + 3X + 5 = 65
4X + 5 = 65
4X = 60
X=15
15 + Y = 65
Y = 50
50 / 15 = 3 with remainder of 5
24 posted on
03/16/2010 10:39:33 AM PDT by
IYAS9YAS
(The townhalls were going great until the oPods showed up.)
To: netmilsmom
Here is a GREAT Algebra web site(It helped a rock like me through it when I was 43 YO): purplemath.com
To: netmilsmom
sum of two numbers is 65 And if the larger number is divided by the smaller number then the quotient is 3 and the remainder is 5. Find the numbers. Let the 2 numbers be 'a' and 'b'.
By specification in the problem: a + b = 65
Also by specification: b = 3 * a + 5 , where b > a
Then, by substitution in the first equation: a + 3 * a + 5 = 65
Or, a + 3 * a = 60 (substracting 5 fr/both sides)
Or, 4a = 60, and thus a = 15
Replacing the value of a into either equation, we see that b = 50.
FReegards!
28 posted on
03/16/2010 10:42:20 AM PDT by
SAJ
(Zerobama? A phony and a prick, ergo a dildo.)
To: netmilsmom
30 posted on
03/16/2010 10:44:15 AM PDT by
E. Pluribus Unum
(Islam is a religion of peace, and Muslims reserve the right to kill anyone who says otherwise.)
To: netmilsmom
I miss math, that was fun! Put me on your ping list for future Algebra problems.
To: netmilsmom
A couple of folks have laid out the basic problem. The key to explaining it is in making clear the second part: A/B = 3r5.
How do you express that remainder as a number (a fraction, actually)?
You express the remainder as a fraction this way: 3r5 is the same as saying 3 + 5/B. You can show this using long division.
Thus:
A/B = 3r5 = 3 + 5/B.
A/B = 3 + 5/B
Multiply both sides by B:
A = 3B + 5
and the rest is set.
35 posted on
03/16/2010 10:45:58 AM PDT by
r9etb
To: netmilsmom
You have two simultaneous equations:
The sum of two numbers is 65
X + Y = 65
And if the larger number is divided by the smaller number then the quotient is 3 and the remainder is 5
(3 * X) + 5 = Y
Now, substitute second equation into first:
X + (3 * X) + 5 = 65
Simplify it:
(4 * X) + 5 = 65
Subtract 5 from both sides:
(4 * X) = 60
And divide both sides by X:
X = 15
Now substitute the 15 back into the first equation:
15 + Y = 65
Subtract it 15 from both sides:
Y = 50
37 posted on
03/16/2010 10:47:58 AM PDT by
justlurking
(The only remedy for a bad guy with a gun is a good WOMAN (Sgt. Kimberly Munley) with a gun)
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