1 posted on
08/11/2004 12:27:04 PM PDT by
weave09
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To: weave09
I was kind of puzzling over the number of keywords
Lando 
2 posted on
08/11/2004 12:29:41 PM PDT by
Lando Lincoln
(A Fair and Balanced Decision - GWB in 2004)
To: weave09
The correct answer is to take 'em fishing instead.
3 posted on
08/11/2004 12:30:54 PM PDT by
Willie Green
(Go Alan Go!!!)
To: weave09
In runnin ght eproblem through my head I am coming up with a not possible solution. You woud need a few more rounds. Sorry...
4 posted on
08/11/2004 12:30:54 PM PDT by
Kate of Spice Island
('Effin the ineffible since '91." FirstIAmAUSSoldier and I approve of this message...)
To: weave09
OK...you can play with three other people in each round; three times four is twelve, so each person will play with exactly one other person twice in a valid solution.
I didn't get heavily into combinatorics in college, but it should be easy to set up a depth-first search routine sort of like the standard eight queens program.
5 posted on
08/11/2004 12:33:19 PM PDT by
jejones
To: weave09
6 posted on
08/11/2004 12:34:09 PM PDT by
Tijeras_Slim
(Be a Dollar a Day FReeper, and SMILE when you get your Mastercard bill!)
To: weave09
7 posted on
08/11/2004 12:35:10 PM PDT by
BigLittle
(Also sad, because it's so close to the truth.)
To: weave09
why were you picked for the scheduling chore?
8 posted on
08/11/2004 12:35:40 PM PDT by
phxaz
(if a fly lies he dies.)
To: weave09
9 posted on
08/11/2004 12:36:08 PM PDT by
scab4faa
("While you're here, you're a Horse's Ass, once you're gone, you're a Hero, I have never been a hero.)
To: weave09
There would be about 50 trillion combinations.
10 posted on
08/11/2004 12:37:16 PM PDT by
RightWhale
(Withdraw from the 1967 UN Outer Space Treaty and establish property rights)
To: weave09
You're looking for info on
Operations Research. I'm sure if you search around, there will be some canned program to help you out.
To: weave09
Just make 'em random each round.
13 posted on
08/11/2004 12:39:43 PM PDT by
leadpencil1
(Somewhere in Massachusetts, a village is missing their DORK)
To: weave09
Your solution is elementary.
To: weave09
Ummm. I'll get back to you on that...
17 posted on
08/11/2004 12:42:26 PM PDT by
bondjamesbond
(We live in a wonderful country where any child can grow up to be the next Ronald Reagan.)
To: weave09
If you start off playing a beer-a-hole, when they get drunk and quit playing, you can just tell them that they all played together.
19 posted on
08/11/2004 12:44:31 PM PDT by
thackney
(life is fragile, handle with prayer)
To: weave09
Pairing the golfers as twosomes and rotating the twosomes in the foursomes almost get you there, but not quite. Does anybody hate eachother in the group?
20 posted on
08/11/2004 12:52:17 PM PDT by
socal_parrot
(If I can just get off of this LA freeway without getting killed or caught)
To: weave09
This seems quite easy (which means I'm sure I'll get it WRONG!). Each golfer is a number, 1 through 12. Assign these 12 golfers the following group numbers:
1. A, a, a, a
2. a, b, c, d
3. a, c, d, b
4. a, d, b, c
5. b, b, b, b
6. b, a, c, d
7. b, d, a, c
8. b, c, d, a
9. c, c, c, c
10.c, a, b, d
11.c, b, d, a
12.c, d, a, c
What did I win? Everyone plays with different person, each day.
21 posted on
08/11/2004 12:58:56 PM PDT by
Shryke
(Never retreat. Never explain. Get it done and let them howl.)
To: weave09
I suggest that after the first round you always pair-up the winning golfers, second place finishers, third place and fourth place from the previous round.
That way every group is broken up each round but you will start with 4 threesomes and end up with 3 foursomes.
26 posted on
08/11/2004 1:05:42 PM PDT by
1smallVoice
(Clinton brought us Bush)
To: weave09
See above, I think that works.
31 posted on
08/11/2004 1:15:54 PM PDT by
Shryke
(Never retreat. Never explain. Get it done and let them howl.)
To: weave09; kevkrom
N/M, it's closer but no cigar. DAMN.
33 posted on
08/11/2004 1:23:58 PM PDT by
Shryke
(Never retreat. Never explain. Get it done and let them howl.)
To: weave09
sorry, tisn't possible
(please don't ask for a proof)
35 posted on
08/11/2004 1:46:46 PM PDT by
fnord
(Being humble doesn't mean thinking less of yourself. It means thinking more of others.)
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