Posted on 05/17/2018 5:43:36 AM PDT by w1n1
I am 9.546% sure this was covered on “Mythbusters.”
I think on Myth Busters they compared dropping a round from a fixed height and comparing it to a bullet shot parallel to the ground from the same height.
They both hit the ground at the same time. Obviously with no lift involved they fell at the same speed but the one shot from a gun was significantly down range. Physics
....about as organised as cat riot...
..we’ll hear from this duo again when they make headlines (fatality)
1 minute , 50 seconds.
Obviously, these boys have way too much time on their hands! LMAO
Yep..................Saw that episode..............
I’ve been hit on the head by falling birdshot shooting crows didn’t even leave a mark...or hurt.
A .50 cal. would probably hurt and it might break the skin but it ain’t gonna kill ya.
Projectile height given time video
Physics would also tell you the time it would take for the bullet to travel in its parabolic arc and return to the ground. Plus its terminal velocity. And, neglecting wind resistance and deflection, its exact trajectory.
Powerful stuff, physics.
Neglecting air resistance, the round would have the same energy it had when it left the muzzle. Not only would it break the skin, it would turn your skull into putty.
Obviously, from the “helicopter” noise the returning round makes, air resistance IS a factor. But I’m betting you still wouldn’t want to get hit.
Under those circumstances a 22 would hit the ground at the same time the 50 caliber did.
Only in a vacuum. The .22 caliber bullet will be affected more by the atmosphere.
That was cool.
The .50 cal will stay in the air a lot longer than the .22 round.
a 50 cal traveling at terminal velocity will definitely hurt. it could easily kill.
(I have a degree in physics- trust me on that)
A shot straight up will go straight up until it stops. It will then fall straight back down, but it will tumble. That is why it makes a windmilling sound.
However, a shot at an angle, say, 10 degrees from vertical, will follow something like parabolic arc, and will still have forward velocity when it reaches the top of that arc. It will then continue down without tumbling, and will gain speed and be moving much faster when it hits the ground.
So a shot straight up may come back down and hit you on the head, but it will probably not kill you, because the bullet will be moving slow, windmilling all the way down. But a shot at a high trajectory that is not vertical will come down, with great energy, some distance away, and would be quite deadly.
One fired at an ISIS terrorist will reach the ground within a second after impact.
But a 50 calibre shot fired perfectly straight up in perfectly calm winds (at the fire point AND all the way to its maximum height will NOT fall back at the fire point. The earth is rotating 1037 mph (1670 km per hour). (Approximately 0.28 mile per second of total non-relativistic vertical flight.)
But that’s at the equator.
Multiple by the cosine of the latitude of the fire point (and add the elevation of the fire point from the assumed perfect spherical global) to get the actual horizontal speed of the perfect bullet fired perfectly upwards in a perfect vacuum - or in a perfectly still air mass.
I’m a nuclear engineer - which is why I know the “actual physics” in the real world can’t be calculated the way most college-educated physicists naively approximate the real world. 8<)
Of course, the initial inertia has to be accounted as well. It’s all relative velocity.
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