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To: AndrewC
It states that a uniform gravitational field (like that near the Earth) is equivalent to a uniform acceleration.

That would be erroneous. The force of acceleration is constant at all vertical displacements. The force of gravity varies with the inverse square of the vertical displacement.

Only in the end case where vertical displacements are zero is there an apparent equivalence. Hence for all non-zero dimensions, gravity and acceleration behave differently.

894 posted on 06/18/2002 7:01:35 AM PDT by jlogajan
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To: jlogajan
Hence for all non-zero dimensions, gravity and acceleration behave differently.

Go get your Nobel Prize, you've disproved Einstein's Principle of Equivalence

Principle of Equivalence

Experiments performed in a uniformly accelerating reference frame with acceleration a are indistinguishable from the same experiments performed in a non-accelerating reference frame which is situated in a gravitational field where the acceleration of gravity = g = -a = intensity of gravity field. One way of stating this fundamental principle of general relativity is to say that gravitational mass is identical to inertial mass. One of the implications of the principle of equivalence is that since photons have momentum and therefore must be attributed an inertial mass, they must also have a gravitational mass. Thus photons should be deflected by gravity. They should also be impeded in their escape from a gravity field, leading to the gravitational red shift and the concept of a black hole. It also leads to gravitational lens effects.
Index

General relativity ideas
  HyperPhysics***** Relativity

900 posted on 06/18/2002 7:16:23 AM PDT by AndrewC
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