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Man killed when car plunges into Grand Canyon
CNN ^ | July 14, 2009

Posted on 07/14/2009 9:33:55 AM PDT by rdl6989

A man died after his car plunged 600 feet off the edge of the Grand Canyon's South Rim, authorities said Tuesday. The Arizona park's regional communications center received several reports of a car driving off the edge about 6 a.m. Monday, according to a written statement.

"Upon arriving at the scene, investigators found tire tracks leading to the edge behind the Thunderbird Lodge and received reports of a single occupant in a blue passenger car driving over the edge," the statement said.

Rescue personnel descended on ropes and found the vehicle about 600 feet into the canyon. The man's body was recovered shortly afterward, the statement said.

The incident occurred near the El Tovar hotel in a village on the canyon's South Rim, park spokeswoman Shannan Marcak said.

Authorities have not ruled the death a suicide, she said. "It has not been ruled anything at this time."

The statement said the National Park Service is investigating. Typically, Marcak said, such investigations take at least a few days.

(Excerpt) Read more at cnn.com ...


TOPICS: Extended News; US: Arizona
KEYWORDS: grandcanyon; terminalvelocity
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To: Abathar

My inlaws went on a helicopter tour of the canyon in June . They said there was a car at the bottom of the canyon that was from a movie . I couldn’t believe it either . I figured that is the only car that went over the rim .


61 posted on 07/14/2009 10:16:31 AM PDT by Renegade (You go tell my buddies)
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To: MikeWUSAF
600ft at 40mph 1 mile = 5280 feet so he went .11 miles Time = Distance ÷ Speed .16 seconds? How’d I do?

Not so good. he was travelling horizontally at 45 mph, theoretically. Adjusting for drag he was probably doing 40 when he hit. But he started at the top at 0 vertically, and accelerated at 32 feet per second, per second.

62 posted on 07/14/2009 10:16:42 AM PDT by jdub (A patriot must always be ready to defend his country against his government.)
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To: So Cal Rocket

His horizontal travel beyond the edge of the cliff would have been ~44 feet; within the first .4 secs the vehicle would have turned nose down and its initial rate of speed would have increased from ~61 fps to roughly 188 fps at impact; time of fall would be ~6.1 secs as previously said.


63 posted on 07/14/2009 10:16:44 AM PDT by Old Professer (The critic writes with rapier pen, dips it twice, then writes again.)
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To: justkate

No. He should get a A for his self esteem even though he had a wrong answer.


64 posted on 07/14/2009 10:16:57 AM PDT by paul51 (11 September 2001 - Never forget)
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To: MikeWUSAF

It’s not a matter of velocity, it’s a matter of how the Sparrow can grasp the coconut in the first place.....


65 posted on 07/14/2009 10:17:30 AM PDT by shredderman (Living in a Blue State, with a Blue Wife, But I'm Red to the bone.....)
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To: Aria
I can’t even stand photos of high places...like construction workers at the top of a skyscraper looking down. Gives me the CREEPS!

LOL - I have a friend who climbs towers to work on broadcast antenna systems. Here is a pic he took while at the top of one:



Personally, I think he's insane.

66 posted on 07/14/2009 10:20:06 AM PDT by reagan_fanatic (When you put Democrats in charge, stupid things happen)
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To: So Cal Rocket

Ok, smarty pants. Assuming the front wheels starting falling before the rear, what was the rotation rate about the pitch axis and what was his pitch angle at impact?


67 posted on 07/14/2009 10:20:19 AM PDT by Lonesome in Massachussets (AGWT is very robust with respect to data. All observations confirm it at the 100% confidence level.)
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To: pappyone

The acceleration from gravity is 32ft/second^2. If you drop a bullet, it’s velocity will increase at 32ft/second per each second. This is true for any object until air resistance starts to come into play.

If you shoot a round straight down it’s initial velocity will be so high, say 1500 feet/second. After one second, its velocity would have increased to 1532 feet/second, assuming zero air resistance.


68 posted on 07/14/2009 10:20:46 AM PDT by Stat-boy
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To: pappyone
No, because you fired the bullet downward. If you fired the bullet across the canyon it would then be affected by gravity and the downward fall would be 32.2 Ft. Per second Squared. The car would not be traveling vertically at 40 MPH, it would be moving horizontally at 40 MPH and that motion would cease to have a driving effect, in other words the wheels would no longer be supplying motion, once the car was off the edge of the cliff. The 40 MPH would have some effect but the downward speed would be 32.2 Ft per second/per second. I believe it would land about 328 ft. OUT and hit the ground in about 6.1 seconds.

A bullet fired downward is a totally different story. Think things through before you ask questions, most of the time you can figure it out.

69 posted on 07/14/2009 10:21:04 AM PDT by calex59
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To: reagan_fanatic

OMG - i think i have to go lie on the ground now....

LOL


70 posted on 07/14/2009 10:21:10 AM PDT by Aria ( "The US republic will endure until Congress discovers it can bribe the public with the people's $.")
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To: pappyone

If you shoot it parallel to the bottom of the canyon it will fall at 32 feet/ sec. squared . If you shoot it toward the bottom it will travel at muzzle velocity to the bottom .


71 posted on 07/14/2009 10:21:33 AM PDT by Renegade (You go tell my buddies)
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To: pappyone
So if I stand on the top of the canyon and shoot a pistol at the bottom, the bullet will only travel 32ft/sec? Just askin, I’m math challenged. I couldn’t add two and two and get 150 billion for a bailout.

No. If you shoot the pistol towards the bottom, then the initial vertical velocity of the bullet is not zero. However, it will accelerate at (1/2)*(32 ft/sec^2) due to gravity.

v(t) = (1/2)at^2 + vt

When driving a car off the edge, there is very little initial vertical velocity (depends on the angle of the ground with respect to the drop-off). Assuming the ground is at a 90-degree angle with the drop-off, there will be no initial vertical velocity (v(0) = 0).

72 posted on 07/14/2009 10:23:10 AM PDT by whd23
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To: shredderman
It could be carried by an African swallow...

73 posted on 07/14/2009 10:23:29 AM PDT by TSgt (Extreme vitriol and rancorous replies served daily. - Mike W USAF)
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To: reagan_fanatic
Oh my gosh!!

Looks like he's climbing a fairly rusty tower!!

I felt safer jumping out of an airplane...a few weeks ago.

74 posted on 07/14/2009 10:24:04 AM PDT by Osage Orange (There ought to be one day-- just one-- when there is open season on senators. - Will Rogers)
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To: Stat-boy

Poor guy. Here he thought “I’m a failure, I’m a nobody, nobody cares for me. Well - I’ll show them. I’ll go out in a blaze of glory and drive off the edge of the Grand Canyon. They’ll ALL know my name then!! Harvey Finklebean - he drove off the edge RIGHT here!”

Instead he becomes a physics example.


75 posted on 07/14/2009 10:24:06 AM PDT by 21twelve (Drive Reality out with a pitchfork if you want , it always comes back.)
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To: reagan_fanatic

I have an FCC license, I used to do all types of work on radios etc, but I would always refuse to do what your friend does. Cost me some bucks but, hey, I never fell off a tower!:)


76 posted on 07/14/2009 10:24:34 AM PDT by calex59
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To: Graybeard58
"drove through"

Ever drive the Going To The Sun road in Glacier National Park? Now that's an experience you won't forget. I was driving, and at one point I asked my wife what was off to the right of my view (couldn't take my eyes off the road). She said she didn't know because she was too scared to look over the side which was about four or five thousand feet down.

77 posted on 07/14/2009 10:26:19 AM PDT by driftless2 (for long term happiness, learn how to play the accordion)
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To: calex59

“The 40 MPH quits as soon as the wheels leave the ground and gravity takes over! “

Not exactly, forward speed will affect the trajectory, but not how quickly he hits the bottom of the canyon. So if his forward speed is sufficient, and the other side low enough he could make it to the other side.

That was the basis for Eviel Kneivel’s stunt, but he may have added elevation (a ramp) to his formula.


78 posted on 07/14/2009 10:26:23 AM PDT by Peter Horry (Never were abilities so much below mediocrity so well rewarded - John Randolph)
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To: Celerity
The only retirement plan left.

Only for those in the private sector...

Those in government continue to receive generous wages, lottery style retirement pensions, top self medical benefits, great job security, since the government at all levels literally refuses to cut back or reduce it size.

We now work for our "public servants" and their security.

79 posted on 07/14/2009 10:26:31 AM PDT by dragnet2
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To: 21twelve

“Instead he becomes a physics example.”

Your comment cracked me up. If I were not a manly man, I would have written “LOL.”


80 posted on 07/14/2009 10:27:05 AM PDT by Stat-boy
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