What numbers? The text provides no data that would allow us to "run the numbers."
They are of necessity for a moon pool to function within a boat - do your research better.
You are mistaken.
Pretty lame.
The volume in Litre (L) in cubic metre (m3)is: 1000L/m3.
21 % of the atmosphere consists of O2 by volume. So, 1000 L of air consists of 0.21 x 1000 L = 210 L of O2.
1 mole of any gas at STP has a volume of 22.4 L. Therefore 210 L of O2 is 210L/22.4L/mole = 9.38 mole.
The mass of 9.38 mole of Oxygen is: 9.38 mole x 32 gram/mole = 300 gram or 0.3 kg.
According to NASA the average person needs 0.84 kg of O2 per day (day and night activity).
So for a room 12 ft wide x 12 ft long x 8 ft ceiling
3.6 m x 3.6 m x 2.4 m = 31.1m3
would last 1 person about 2.6 days, divide that by the total number if more than one. Does not include respiration by animals or other biological activity.
Now consider crossing the pacific ocean, from the article of the thread "Ether describes heavy seas (" . . . they were many times buried in the depths of the sea, because of the mountain waves which broke upon them" 6:6). So these boats were crashing around under water, occasionally flipping upside down (thus the need for a hole in the bottom which could be opened as an air hole when the boat flopped over)." Pacific storms would keep them bottled up for days - still having problems doing the math?
They are of necessity for a moon pool to function within a boat - do your research better.
You are mistaken.
Google 'moon pools' Logo. You will find that even your best scenario would require the sides of the moon pool to be quite deep ( greater than the draft of the ship by a margin of safety) in order not to sink the boat.