Posted on 11/20/2011 1:10:31 PM PST by South40
Herman Cain was the winner of a statewide presidential straw poll announced Saturday of all Missouri Tea Party members.
With 995 total votes counted statewide, Ron Paul and Newt Gingrich were virtually tied for second at 28 percent of the vote each.
Poll totals were: Herman Cain, 320 (32 percent); Ron Paul, 282 (28 percent); Newt Gingrich, 276 (28 percent); Mitt Romney, 32 (3 percent); Michele Bachmann, 31 (3 percent); Rick Perry, 30 (3 percent); Rick Santorum, 13 (1 percent); Others, 2 percent.
Philip Todd said the one-week poll was conducted between Nov. 10 and Nov. 17 throughout Missouri.
James Holland, a Callaway County Patriot Tea Party leader, said he was not surprised by the results or by the fact that Romney, a consistent front runner in many nationwide presidential polls, had only 3 percent of the vote in the statewide poll of Tea Party members.
(Excerpt) Read more at fultonsun.com ...
Sure is...
Neither.
I like pizza.
now we know and see why the leaders on the left have to give these fools bumper sticker slogans, they’re all dumb.
Ask them the merits of their slogans and they looked dumbfounded.
![]() |
bump.
Yes, I agree. And can you believe some are pushing Tea Party supporters to lay down for Romney? Sick!
Disclaimer: Opinions posted on Free Republic are those of the individual posters and do not necessarily represent the opinion of Free Republic or its management. All materials posted herein are protected by copyright law and the exemption for fair use of copyrighted works.