And no photons?
That's right. Photons as such exist only below the electroweak breaking scale; they are really a low-energy mixture of two fundamental electroweak bosons. From Introduction to High Energy Physics by Donald H. Perkins, 3rd Edition, p. 322:
The fundamental vector bosons are a massless isovector triplet Wmu = Wmu(1), Wmu(2), Wmu(3) (for SU(2)) and a massless isosinglet Bmu (for U(1)). As a result of spontaneous symmetry breaking, three bosons (denoted Wmu+, Wmu-, and Zmu0) acquire mass, and one (Amu, the photon) remains massless. These four bosons are combinations of Wmu and Bmu...
(The "mu" is supposed to be a lowercase Greek letter mu.)
Above the electroweak breaking scale, you have W1, W2, W3 and B, which are the fundamental bosons; below that scale, you have W+, W-, Z0, and the photon, which are mixtures.