[Physicist]

And no photons?

That's right. Photons as such exist only below the electroweak breaking scale; they are really a low-energy mixture of two fundamental electroweak bosons. From Introduction to High Energy Physics by Donald H. Perkins, 3rd Edition, p. 322:

The fundamental vector bosons are a massless isovector triplet W_mu = W_mu⁽¹⁾, W_mu⁽²⁾, W_mu⁽³⁾ (for SU(2)) and a massless isosinglet B_mu (for U(1)). As a result of spontaneous symmetry breaking, three bosons (denoted W_mu⁺, W_mu^-, and Z_mu⁰) acquire mass, and one (A_mu, the photon) remains massless. These four bosons are combinations of W_mu and B_mu...

(The "mu" is supposed to be a lowercase Greek letter mu.)

Above the electroweak breaking scale, you have W1, W2, W3 and B, which are the fundamental bosons; below that scale, you have W+, W-, Z0, and the photon, which are mixtures.

[AndrewC]

Above the electroweak breaking scale, you have W1, W2, W3 and B, which are the fundamental bosons; below that scale, you have W+, W-, Z0, and the photon, which are mixtures.

Ahh, then there are no fundamental particles, everything is a mixture of massless things and the Higgs boson which is also rather elusive?