27 kg
I made three rectangles with the weights in them and worked out the percentages of overlap. Cat = 7 Rabbit = 3 Dog = 17 = 27
Thank you for posting this question. Sometimes we need to take a break and do something different.
C + R = 10
D + R = 20
D + C = 24
D + (10 - R) = 24
D = 20 - R
20 - R + 10 - R = 24
30 - 2R = 24
2R = 8
R = 4
D= 16
C = 6
Tl = 26
C + R = 10
D + R = 20
D + C = 24
D + (10 - R) = 24
D = 20 - R
20 - R + 10 - R = 24
30 - 2R = 24
2R = 6
R = 3
D= 17
C = 7
Tl = 27
What is the name of the dog?
Is this the weight before my dog rips they head off of the rabbit?
Algebra? Wouldn’t simple arithmetic do the job?
If a steamship weighed 10,000 tons and sailed 5,000 miles
With a cargo large of overshoes and carving knives and files
If the mates were almost six feet high and the bos’n near the same
Would you subtract or multiply to find the captain’s name?
Let’s assume the weights of the cat, rabbit, and dog are represented by the variables C, R, and D respectively.
From the given information, we can set up a system of equations:
C + R = 10 (Cat and Rabbit weigh 10kg together)
D + R = 20 (Dog and Rabbit weigh 20kg together)
C + D = 24 (Cat and Dog weigh 24kg together)
We can solve this system of equations to find the values of C, R, and D.
From equation 1, we can isolate C: C = 10 - R
From equation 2, we can isolate D: D = 20 - R
Now substitute these expressions for C and D into equation 3:
(10 - R) + (20 - R) = 24
Combine like terms:
30 - 2R = 24
Subtract 30 from both sides:
-2R = -6
Divide by -2:
R = 3
Now that we have the weight of the rabbit (R = 3 kg), we can substitute it back into equations 1 and 2 to find the weights of the cat and the dog:
From equation 1: C = 10 - R = 10 - 3 = 7 kg
From equation 2: D = 20 - R = 20 - 3 = 17 kg
So, the weights of the cat, rabbit, and dog are C = 7 kg, R = 3 kg, and D = 17 kg.
Finally, to find the total weight of all three animals together:
Total weight = C + R + D = 7 + 3 + 17 = 27 kg
Therefore, the total weight of the cat, rabbit, and dog together is 27 kg.
Easy.
2C + 2D + 2R = 54
Divide each side by 2:
C + D + R = 27.
Kids have word problems this week? Ha ha.
I sucked at algebra….
This works because each variable is used twice. I used this same trick in a spreadsheet to find the grand total of a column which contained subtotals for each group of numbers.
I have not looked at any replies to your post.
C + R = 10
D + R = 20
The dog weighs 10 pounds more than the cat.
D = C + 10
C + D = 24
C + (C + 10) = 24
2C = 14
C = 7
R = 10 − 7 = 3
D = C + 10 = 17
Total weight = C + D + R = 27kg
All of them together weigh 27 kg.