“The coefficient of friction changes with normal force (weight).”
Not really all that much over actual vehicle load variation.
Sure, but aren’t we talking about making the vehicle light enough to reduce mpg?
I see how this would be effective in an aircraft (brilliant, I think), but the “buoyancy” would impact a car differently because it interacts with the road. Many attributes of a vehicle are designed around the weight.
What if it weighed 100 pounds? Great for aircraft, not for cars.
(Not arguing - please don’t make me do the math!)
;)
Oh, I just realized that I was incorrect in my first post and your statement is correct.
Force of friction = normal force * coefficient of friction.
You are correct, coefficient of friction does not change signicantly in this case.
But as normal force is reduced, force of friction reduces proportionally.
A one ton car that “weighs” 100 pounds because it has a balloon in it has mass, but can’t accelerate or decelerate very well.
Now winding up with my last whiskey this evening.
:>)