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To: Conan the Librarian
> This doesn’t invalidate Heisenberg. You still aren’t observing the original particle to get it’s data. <

That was my first thought as well. They just made their “particle” really big. So maybe if a particle is big enough, you can measure it’s position without appearing to change its velocity.

But, hey. I got my degree from Faber College. So what do I know?


18 posted on 05/16/2021 10:01:05 AM PDT by Leaning Right (I have already previewed or do not wish to preview this composition.)
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To: Leaning Right

Valid, but, I shall wait to have my mind changed! Then again, all science books should be written in pencil so that changes can be easily made.


48 posted on 05/16/2021 2:09:44 PM PDT by Conan the Librarian (Conan the Sailing Librarian)
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To: Leaning Right
You have the essence of it.

You can measure the position and momentum simultaneously; but the product of the uncertainties in each measurement, must be on the order of Planck's constant or greater.

54 posted on 05/16/2021 3:01:35 PM PDT by grey_whiskers (The opinions are solely those of the author and are subject to change with out notice.)
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