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U.S. Air Force asks industry for proposals to replace nuclear missiles
reuters.com ^ | 07/29/2016

Posted on 07/30/2016 11:03:39 AM PDT by BenLurkin

The Air Force said in a statement it expected to award up to two contracts for a new ICBM weapons system, or ground-based strategic deterrent, sometime next summer or fall. It also expected to award up to two contracts in the same time frame for a new nuclear cruise missile, or long-range standoff weapon.

Modernization of the U.S. nuclear force is expected to cost more than $350 billion over the next decade as the United States works to replace its aging systems, including bombs, nuclear bombers, missiles and submarines. Some analysts estimate the cost of modernization at $1 trillion over 30 years.

The new ICBM system would be a follow-on to the Minuteman missile, whose launch systems and physical infrastructure first became operational in the mid-1960s. The system has been upgraded over the years, but much of the infrastructure is original, the Air Force said.

The most recent versions of the Minuteman III date from the late 1990s and early 2000s and had an intended 20-year life span, the Air Force said. The missile will "face increased operational and sustainment challenges until it can be replaced,"

(Excerpt) Read more at reuters.com ...


TOPICS: Business/Economy
KEYWORDS: icbm; icbms; usaf
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To: Campion
You missed a factor if 2.54 in your volumetric conversion (should be 2.54 CUBED, not squared). Area is about 0.0046 m^2; length is 0.914 meters. Density of tungsten is 19600 kg/m^3, so the mass would be 81.7 kg (that's the difference of the missing 2.54).

Using the equation for terminal velocity, integrating the pull of gravity and air density, and using a Cd around 0.0006 (about what a thin, guided rod would have - typical for an arrow) I get a terminal velocity that is really high - around 31,000 meters per second. Is that reasonable? Well, there is essentially zero cross section, a lot of mass, zero drag, low air density for most of the flight, and lots of distance for gravity to work over...

Sanity check: most meteorites strike around 17,000 m/s so given we're quite a bit more aerodynamic than a meteorite, it's not all that unbelievable.

One kiloton of TNT is about 4.2 gigajoules, which is a lot smaller than your number (which seems to be about 1000 times too high). Run it all, and you're around 11-12 kilotons of energy.

Unless I'm off somewhere!

21 posted on 07/30/2016 12:48:55 PM PDT by Shanghai Dan
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To: BenLurkin

I’m happy to announce that the Timpanagos Nuclear Missile Company will be submitting a bid to build the nuclear missiles for the USAF.

I hope there is enough room in my garage.


22 posted on 07/30/2016 1:18:36 PM PDT by Timpanagos1
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To: Shanghai Dan
You missed a factor if 2.54 in your volumetric conversion (should be 2.54 CUBED, not squared).

Aw, come on, how many of us has not done that a few times?

No way I would post any calculation unless I wrote it all out and triple checked it.

23 posted on 07/30/2016 1:22:57 PM PDT by doorgunner69
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To: Campion; ClearCase_guy
You know, when people say “do the math”, they generally don’t expect that anyone will actually do the math...

The problem is that there is an error in the math. The conversion from cubic inches to cubic centimeters is 2.54^3, not 2.54^2 as given in the calculation presented.

24 posted on 07/30/2016 1:35:43 PM PDT by CurlyDave
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To: Campion

PBS Campion episode on youtube:

https://www.youtube.com/watch?v=Ab65qukjJQA


25 posted on 07/30/2016 1:46:56 PM PDT by JohnnyP
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To: Timpanagos1
You'll need some R&D office space, too...


26 posted on 07/30/2016 2:05:36 PM PDT by Charles Martel (Endeavor to persevere...)
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To: Campion

Rod from God are not Earth launched ballistic objects. They launch from space platforms and can achieve far greater speeds than Mach 25.


27 posted on 07/30/2016 2:06:21 PM PDT by CodeToad (Islam should be banned and treated as a criminal enterprise!)
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To: Shanghai Dan
Point taken about missing the inches->centimeters on the length. Multiply my result by 2.54.

Meteorites may hit the upper atmosphere at 17000 m/s, but they sure don't hit the ground at that speed. And your tungsten pole is coming from orbit, not deep space, so it starts out at orbital velocity, about 8000 m/s.

Gravity will buy you a little coming from orbital altitude, but not 24,000 m/sec, and especially not 24,000 m/s through the atmosphere. A terminal velocity, at the earth's surface, of 31,000 m/s (that's 69,000 miles/hour, faster than *any* manmade object has *ever* gone, by a factor of almost two) ... that's completely impossible.

A kiloton is equal to 4.184 TERAjoules, not gigajoules. (It's in your link.)

28 posted on 07/30/2016 2:09:31 PM PDT by Campion (Halten Sie sich unbedingt an die Lehre!)
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To: CodeToad

If they’re launching from orbit, they’re starting at Mach 25. To enter the atmosphere, they have to slow down, not speed up. (If you’re in orbit and you speed up, you go to a higher orbit, or you achieve escape velocity and leave earth.)


29 posted on 07/30/2016 2:11:27 PM PDT by Campion (Halten Sie sich unbedingt an die Lehre!)
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To: Shanghai Dan

Descending from orbital altitude (assumed to be 270 miles), assuming gravity is constant from ground to 270 miles (it isn’t, so this estimate is high), gives you sqrt(2 * g * d-in-meters) or sqrt(2 x 9.8 x (270 * 1,609)) or a bit over 2900 m/sec. So if there were no atmosphere, you could hit a target on the ground from orbit at 8000+2900 m/sec or about 11,000 m/sec, best case.


30 posted on 07/30/2016 2:39:27 PM PDT by Campion (Halten Sie sich unbedingt an die Lehre!)
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To: Campion
From my shallow understanding of orbital mechanics, the slow down speed up is assuming a velocity vector in the direction of travel.

What happens if the thrust is directly down toward earth? I know de-orbiting space capsules have to be careful not to come in too steep and burn up, but with a rod, just make it steep enough to retain velocity?

31 posted on 07/30/2016 2:42:36 PM PDT by doorgunner69
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To: Campion
A kiloton is equal to 4.184 TERAjoules, not gigajoules. (It's in your link.)

In the immortal words of Homer J. Simpson:


32 posted on 07/30/2016 3:29:57 PM PDT by Shanghai Dan
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To: Campion

“If they’re launching from orbit, they’re starting at Mach 25. To enter the atmosphere, they have to slow down, not speed up. (If you’re in orbit and you speed up, you go to a higher orbit, or you achieve escape velocity and leave earth.)”

Umm....no.

You only escape Earth’s gravity if you are headed away from Earth. If they are accelerating towards Earth how do they leave Earth??


33 posted on 07/30/2016 6:41:09 PM PDT by CodeToad (Islam should be banned and treated as a criminal enterprise!)
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To: Shanghai Dan
One kiloton is 4.184 terajoules, not gigajoules. That's a factor of 1000.

So, if the rest of your calculation is correct, that's 11 or 12 tons of TNT, which would place in the upper range of conventional aerial bombs.

34 posted on 07/30/2016 6:54:13 PM PDT by cynwoody
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