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USGS: Some Earthquakes on San Andreas Fault Are Triggered by Gravitational Tug Between Sun and Moon
Los Angeles Times ^ | 07/18/2016 | Rosanna Xia

Posted on 07/18/2016 7:49:56 PM PDT by BenLurkin

Like sea levels, the surface of the Earth also goes up and down with the tides, flexing the crust and stressing the faults inside....

“...[T]he moon, when it's pulling in the same direction that the fault is slipping, causes the fault to slip more – and faster,” said Nicholas van der Elst, a U.S. Geological Survey geophysicist...

...

Like ocean tides, the strongest Earth tides occur when the sun and moon are aligned, and the weakest occur when they are 90 degrees apart. The same gravitational forces stretch and compress the Earth’s crust (though the rock moves less dramatically than seawater).

Some faults are more susceptible to tidal triggering than others, such as offshore faults like the Cascadia subduction zone off the Pacific Northwest coast, scientists said. Other characteristics of the fault, such as its orientation or how close it is to the Earth’s crust, also affect the tidal response. 'Seismic strain': Land around the San Andreas fault is rising and sinking, new earthquake research shows 'Seismic strain': Land around the San Andreas fault is rising and sinking, new earthquake research shows

...

...

They also show that this part of the San Andreas is creeping, or slowly moving, almost all the time....

...

“So if all of a sudden, we saw that the deep part of the fault was slipping a huge amount, it might be an indication that there was an increased chance of having an earthquake come at the shallower part of the fault,” he said.

...

It’s like the fault has an earthquake budget...“If you used them up yesterday, you don’t have as many to trigger today. By actually measuring that, we get an estimate of what that stress budget is.”

Essentially, scientists now have a way to measure the fault’s recharge time in certain locations.

(Excerpt) Read more at latimes.com ...


TOPICS: Science
KEYWORDS: earthquakes; sanandreasfault; sunandmoon; usgs
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To: BenLurkin

This is a total fantasy.

Everyone knows when a whole bunch of dogs start barking at the same time earthquakes happen.


21 posted on 07/18/2016 8:45:18 PM PDT by disndat
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To: BenLurkin

Not so. They are caused by climate change.


22 posted on 07/18/2016 8:48:38 PM PDT by TruthWillWin (The problem with socialists is that you eventually run out of other peoples money.)
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To: BenLurkin

Jim Berkland, please pick up the white courtesy geophone...


23 posted on 07/18/2016 8:59:18 PM PDT by null and void (Has there ever been a death associated with the Clintons that *wasn't* beneficial to them?)
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To: onedoug

ping


24 posted on 07/18/2016 9:00:04 PM PDT by windcliff
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To: Vision Thing

Sounds like an engineering nightmare.


25 posted on 07/18/2016 9:01:44 PM PDT by Rebelbase ( Pokemon is a dark evil bent on consuming our souls.)
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To: BenLurkin

If gravity between large heavenly bodies has anything to do with it..

Who ya gonna call? GHostbusters? :-)


26 posted on 07/18/2016 9:01:57 PM PDT by NormsRevenge (SEMPER FI!! - Monthly Donors Rock!!)
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To: BenLurkin

Quakes have been around 2.0 but they are patterning like a zipper.
Similar depth and one seems to trip off two others.
This is a different pattern than I’ve been seeing during the last year.

Probably nothing but I do think it is interesting to watch.
If we start seeing a growing quantity or intensity, this would be a change from the norm.

I have a theory that very large quake tend to de-stablize the Ring of Fire.
We have seen Great Quakes in the last 10 years in all of the key areas around the Ring of Fire with the exception of the west coast of the USA/Canada

For 5 years I’ve been casually monitoring quake activity in the Pacific and actually predicted a very large one in Kamchatka about 3 years ago.


27 posted on 07/18/2016 9:04:03 PM PDT by Zathras
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To: Mark17
I thought earthquakes were caused by global warming. S/

Oh, sure, laugh if you will.

Everyone knows Global WarmingTM is caused by human activity, (specifically by selfish Americans), and that if we all don't cut all electricity to our homes, destroy our evil SUV's and quit exhaling that Erf destroying C02 , we're all going to die!

Do you really want to die because of your poor life choices?!

28 posted on 07/18/2016 9:07:19 PM PDT by PROCON (Americans First or Terrorists First - Choose in November)
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To: PROCON
Do you really want to die because of your poor life choices?!

Hmmmm. I'll have to think about that. 😀😀😄

29 posted on 07/18/2016 9:13:22 PM PDT by Mark17 (The love of God, how rich and pure, how measureless and strong. It shall forevermore endure.)
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To: Zathras

The tidal force of a nearby object is proportional to the inverse CUBE of its distance times the mass of the object. This happens to be the density of the object times the cube of the ratio of its diameter to its distance.

But the apparent diameter in the sky of this object is simply the ratio of its diameter to its distance, so the tidal force is proportional to its density times the cube of its apparent diameter.

( This is my own observation, BTW. )

Thus, since the sun and moon have about the same apparent diameter ( nearly exactly, in fact ) the lesser tidal force of the sun is a demonstration of its lesser ( average ) density.

Also, with the density of the other planets being the same or somewhat less than the moon, it follows that their tidal influence is limited by the cube of their apparent diameters, making this influence in each case very much less than the tidal influence of the moon or sun. You do the math!


30 posted on 07/18/2016 9:14:51 PM PDT by dr_lew
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To: Mark17

LOL, some of these earthquake, hurricane, earth-destroying comet threads just drive me nuts. :-)


31 posted on 07/18/2016 9:18:35 PM PDT by PROCON (Americans First or Terrorists First - Choose in November)
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To: 43north

The moon being full has nothing to do with it’s gravity....it doesn’t change.


32 posted on 07/18/2016 9:25:00 PM PDT by FreedomStar3028 (Somebody has to step forward and do what is right because it is right, otherwise no one will follow.)
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To: SpaceBar

Agreed.


33 posted on 07/18/2016 9:34:42 PM PDT by onedoug
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To: dr_lew

I can do the math.
I have the density part down to a tee.


34 posted on 07/18/2016 9:47:06 PM PDT by Rockpile (GOP legislators-----caviar eating surrender monkeys.)
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To: Rockpile
I can do the math.
I have the density part down to a tee.

Well, how about the apparent diameter part? I'm on tenterhooks.

35 posted on 07/18/2016 9:51:40 PM PDT by dr_lew
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To: dr_lew

Apparent diameter? Those bodies have a round shape like me.

But you don’t want to see my moon.


36 posted on 07/18/2016 9:55:55 PM PDT by Rockpile (GOP legislators-----caviar eating surrender monkeys.)
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To: BenLurkin

bookmark


37 posted on 07/18/2016 9:59:45 PM PDT by GOP Poet
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To: Rockpile
Apparent diameter?

This is, in other words, the angular diameter of the object as it appears in the sky, expressed in radians. The apparent diameter of the sun and the moon is about 1/100, meaning that they are each distant from the earth by about 100 of their own diameters ( rule of thumb. )

38 posted on 07/18/2016 10:06:58 PM PDT by dr_lew
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To: FreedomStar3028

The Moon being Full means it is on the opposite side of the Earth from The Sun, so it is like the Sun pulling one of your arms, and the Moon is pulling your other arm and they are trying to split you in two.


39 posted on 07/18/2016 10:34:06 PM PDT by Joe Miner
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To: FreedomStar3028

I believe the reference is to the alignment of the sun and the moon, which occurs at “full” and “new” moons. These correspond to “spring tides” as opposed to “neap tides”, which occur at the first and third quarter moon.

I think this is all very tenuous reasoning, but it does make some kind of sense that the response, in the form of an earthquake, would occur at the maximum of the presumed influence, i.e. at “spring tide”.


40 posted on 07/18/2016 10:44:11 PM PDT by dr_lew
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