Replies

To: HangnJudge

...and i^i = e^(-pi/2)

27 posted on 02/20/2016 2:41:29 PM PST by beethovenfan (Islam is a cancer on civilization.)

To: beethovenfan

...and i^i = e^(-pi/2)

I don't care if ¿Jeb? said to, I'm *still* gonna clap!

42 posted on 02/20/2016 3:43:27 PM PST by grey_whiskers (The opinions are solely those of the author and are subject to change without notice.)

To: beethovenfan

I haven't seen that before and it uses the Euler identity in the derivation
Fascinating

50 posted on 02/20/2016 4:09:52 PM PST by HangnJudge (Cthulhu for President, why vote for a lesser Evil)

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