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To: Red Badger

In laymens terms, What?

What practical applications does this actually mean? Smaller electrionics due to increased signal strength?


7 posted on 01/20/2015 1:16:16 PM PST by Obadiah (If the RINOs engineer the 2016 Primary for their guy, I will sit out the General for my guy.)
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To: Obadiah

communications, imaging, computing...........

Imaging, for instance a camera that can see in very dark areas..................


9 posted on 01/20/2015 1:18:34 PM PST by Red Badger (If you compromise with evil, you just get more evil..........................)
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To: Obadiah

I imagine it’ll help with budgeting signal loss in fiber optics. Right now long range fiber has a loss per km. Better amplification I presume could allow longer distance between amplifiers which reduces latency, errors, and infrastructure.


17 posted on 01/20/2015 1:31:34 PM PST by Bogey78O (We had a good run. Coulda been great still.)
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To: Obadiah

Smaller electronics, yes but not solely due to increased signal strength. There is also significant reduction in noise. This will work to reduce the need for post signal filtering and correction. Possibly removing substantial amounts of post signal correction.

Of the two positives (better signal strength and lower noise), I am of the opinion that lower noise will remove more of the size of components from the mix.


18 posted on 01/20/2015 1:34:54 PM PST by taxcontrol
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