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Vanity! Anyone here have good working trigonometry function skills?
August 2, 2011 | me

Posted on 08/02/2011 6:46:39 PM PDT by jsh3180

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To: poindexters brother
using tan(x) = pop / adj hyp^2 = s1^2 + s2^2 s1 = 342.21 s2 = 104.625 hyp = 343.7

Sigh... Ignore that answer... Got my diagrams fouled up.

21 posted on 08/02/2011 7:01:35 PM PDT by poindexters brother
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To: Sacajaweau

Whoops...read it wrong...


22 posted on 08/02/2011 7:01:40 PM PDT by Sacajaweau
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To: jsh3180
104.625 is vertical from the base of the triangle, with the 17 degree angle at the top of the 104.625 side

so then x = 104.625/cos(17)

Make sure your calculator is in "Degrees" mode and not "Radians" mode or everything will go crazy fast.

23 posted on 08/02/2011 7:01:40 PM PDT by Tanniker Smith (I didn't know she was a liberal when I married her.)
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To: jsh3180

Your numbers are wrong. All triangles have a total of 180 degrees on the internal angle. No more, no less.


24 posted on 08/02/2011 7:01:46 PM PDT by Blood of Tyrants (Islam is the religion of Satan and Mohammed was his minion.)
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To: jsh3180

The numbers you offer are ambiguous.

There are two solutions unless you identify specifically which angle is opposite the given side.


25 posted on 08/02/2011 7:01:56 PM PDT by editor-surveyor (Going 'EGYPT' - 2012!)
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To: jsh3180

Draw the picture...base is longer or height (104.625) is longer?? We need the position of the angles.


26 posted on 08/02/2011 7:03:17 PM PDT by Sacajaweau
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To: pabianice
I know just how you feel! 10th grade Geometry construction has saved my butt so many times!
27 posted on 08/02/2011 7:03:17 PM PDT by WellyP (REAL)
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To: Blood of Tyrants
One of the three numbers is a length.
The right triangle's angles are 17-73-90.
28 posted on 08/02/2011 7:03:17 PM PDT by Tanniker Smith (I didn't know she was a liberal when I married her.)
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To: jsh3180

sin(73*)=104.625/x
0.956=104.625/x
0.956x=104.625
x=109.406

Incidentally, the third side is length 31.987, the proof of which is left as an exercise for the reader.


29 posted on 08/02/2011 7:03:37 PM PDT by Turbopilot (iumop ap!sdn w,I 'aw dlaH)
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To: jsh3180

Draw the picture...base is longer or height (104.625) is longer?? We need the position of the angles.


30 posted on 08/02/2011 7:04:32 PM PDT by Sacajaweau
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To: EEGator

Thanks, EEGator, I believe that is correct. I knew the short leg of the 90 degree side was going to be somewhere between 24 and 36.
Reason for my question,in case you want to know, I’m building a custom stair/ladder that is pretty steep. Not much material to experiment with and I want to be right on when I cut.

Thanks!!!


31 posted on 08/02/2011 7:04:49 PM PDT by jsh3180
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To: DuncanWaring

You don’t need that. It’s a right triangle.


32 posted on 08/02/2011 7:04:52 PM PDT by Tanniker Smith (I didn't know she was a liberal when I married her.)
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To: jsh3180

Your problem state that a line intersects an angle. How is this possible?


33 posted on 08/02/2011 7:06:51 PM PDT by loungitude ( The truth hurts.)
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To: EEGator; jsh3180

Agreed.


34 posted on 08/02/2011 7:06:58 PM PDT by 1066AD
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To: jsh3180

You’re welcome. Measure twice, cut once.


35 posted on 08/02/2011 7:07:09 PM PDT by EEGator
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To: jsh3180

Oops. Sorry.

Sine(x) = length opposite/length hypotenuse
Cosine(x)= length adjacent/ length hypotenuse
Tan(x) = Length opposite/ length adjacent

From these three you can calculate all the other sides and angles.


36 posted on 08/02/2011 7:07:40 PM PDT by Blood of Tyrants (Islam is the religion of Satan and Mohammed was his minion.)
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To: Tanniker Smith

I do believe you’re correct on that one, on reconsideration.


37 posted on 08/02/2011 7:09:35 PM PDT by DuncanWaring (The Lord uses the good ones; the bad ones use the Lord.)
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To: jsh3180

It was a long story but the answer is The Squaw On The Hippopotamus Is Equal To The Sum Of The Squaws On The Other Two Hides.


38 posted on 08/02/2011 7:09:53 PM PDT by ThomasThomas (I am still looking)
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To: Turbopilot
the proof of which is left as an exercise for the reader.

Brings back memories !!

39 posted on 08/02/2011 7:10:17 PM PDT by 1066AD
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To: editor-surveyor

The numbers you offer are ambiguous.

There are two solutions unless you identify specifically which angle is opposite the given side.


Depending on the relation of the given angles to the side given, the possible values of the hypotenuse are 109.406 and 357.851. (I think) BSEE ‘64


40 posted on 08/02/2011 7:14:54 PM PDT by bytesmith
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