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Can anyone help with A=2-log %T ??
11/13/2010
| Me
Posted on 11/13/2010 6:27:32 PM PST by paul544
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Thanks for any help.
1
posted on
11/13/2010 6:27:34 PM PST
by
paul544
To: paul544
You signed up in 2000 just to get help with chemistry???
(Other than mixology, I haven’t done chemistry in over 30 years...)
To: paul544
Lol, I’m not even smart enough to understand the question.
3
posted on
11/13/2010 6:31:10 PM PST
by
rdl6989
(January 20, 2013- The end of an error.)
To: paul544
4
posted on
11/13/2010 6:32:08 PM PST
by
cripplecreek
(Remember the River Raisin! (look it up))
To: freedumb2003
why don’t you answer his question and not be a smart ass?
The maximum number in % is 100%. This is the big clue.
Then split -log (%T) in -Log % and -Log T. Replace % with 100.
Log (100) = 2. After that you have A = 2-2-log T. And this becomes A=- log T. Therefore A = -log T.
Do an example by filling T=5.
Then you have 2- log (100*5) = -0.69897 or log (5) is also -0.69897.
Hope this helps.
* 3 years ago
5
posted on
11/13/2010 6:32:18 PM PST
by
edcoil
(Today, we start fixing stupid.)
To: paul544
Which part of the equation is the problem for you?
6
posted on
11/13/2010 6:33:42 PM PST
by
Tolerance Sucks Rocks
(Muslims are not the problem, the rest of the world is! /s)
To: paul544
I can do homework professionally (gack, I'm back to this? The economy really, reaaly needs to improve), but I charge steeply, depending on the degree you are seeking. Specials on term papers.
Work it dude. You can do it.
Asking for help for homework in class is ok. Maybe not so much on a public forum.
/johnny
To: paul544
If I'm not mistaken, that formula is used to determine the best brewing temperature of beer.........
I might be wrong tho so here's a pingster for someone who might be more knowledgable in these things.........
8
posted on
11/13/2010 6:35:27 PM PST
by
Hot Tabasco
(There's only one cure for Obamarrhea......)
To: edcoil
Someone got up on the wrong side of the bed today...
To: Tolerance Sucks Rocks
I’m assuming you don’t leave the % as a whole number... So, up to this point I’ve been converting it to, say .25. If that is right, then I’m going with the log of .25 but that doesn’t seem right. I’ve seen where it might be 1/.25 then log...
10
posted on
11/13/2010 6:37:37 PM PST
by
paul544
To: paul544
11
posted on
11/13/2010 6:38:32 PM PST
by
Drango
(NO-vember is payback for April 15th)
To: edcoil
I'll bet you didn't use (human readable) log tables or a slipstick. Not with that many decimal points.
/johnny
To: freedumb2003; paul544
13
posted on
11/13/2010 6:38:53 PM PST
by
Vendome
(Don't take life so seriously... You'll never live through it.)
To: edcoil
Thanks. I saw that out there as well. I’ve been trying to use it and think it helps. Appreciate it.
14
posted on
11/13/2010 6:39:38 PM PST
by
paul544
To: paul544
Are you having trouble with the math or the chemistry?
For the math you just need to clarify if %T should be 25 or .25, and then compute the answer.
15
posted on
11/13/2010 6:39:53 PM PST
by
devere
To: edcoil; freedumb2003; paul544
Geeze edcoil:
It’s Saturday Night and paul544 has been on here long enough to take a razzing.
Probably knew he was going to get a few anyway.
BTW paul544 the answer is log - 42 = %. /s
16
posted on
11/13/2010 6:42:32 PM PST
by
Vendome
(Don't take life so seriously... You'll never live through it.)
To: JRandomFreeper
Now that’s funny.
getting some popcorn...
17
posted on
11/13/2010 6:43:54 PM PST
by
Vendome
(Don't take life so seriously... You'll never live through it.)
To: devere
I get the chemistry for the most part.
The issue is when I see 2-log, I’m not sure of the math to apply to the %. If I make the 25%, .25, is the next step just applying the log function or is there another step?
18
posted on
11/13/2010 6:44:07 PM PST
by
paul544
To: Vendome
Chem tip of the day: Never mix ammonia with bleach...produces lung searing gasses that can off you.
19
posted on
11/13/2010 6:44:14 PM PST
by
JPG
(The GOP leadership is on probation. No second chances. Don't blow it.)
To: cripplecreek
Dang...you beat me to it...The quicker, picker-upper" LOL
20
posted on
11/13/2010 6:45:00 PM PST
by
FrankR
(Don't let the bastards wear you down!)
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