I’m assuming you don’t leave the % as a whole number... So, up to this point I’ve been converting it to, say .25. If that is right, then I’m going with the log of .25 but that doesn’t seem right. I’ve seen where it might be 1/.25 then log...
Yes, you leave it as a whole number (see my prior post)
Well, if your absorbancy values appear to be way off, compared to any examples offered, then you might indeed need to use the whole number for % (e.g. 25 = 25%). I’m surprised that your lab text apparently did not make that clear.