His email is available, freemail me if you want to discuss directly with him.
I'll try to get him to login on new his account in FreeRepublic as well.
My other questions: If it's a square plate being modelled (then his pier would have to be a rectangle or square itself incross-section. That resistance would not be the same as a flat (very thin) plate since a rectangle has drag along both sides, as well as face, corner, and exit losses.
If it's a flat square )thin) plate in the current, then it won't be able to carry a load: only create resistance like a brake.
You wanna field this one?
Scrstching head trying to recall; dont you do the drag coeeficient
My guess is zero.
bah typos
should be:
Scratching head trying to recall; dont you do the drag coefficient
And my guess of zero is wrong but its been about 25 yrs since I messed with this type of equation and plugging in numbers thats what I got, but obviously something I did was wrong :)
R = 0,5*Ro*c*Aw*v^2
I know you need 6lb drag setting to bring in a 7lb rainbow.
Is the flow perp to the face and supported only by the neglected supports? Open channel here means the cross sectional area of the pipe is not significantly effected by the plate right?
I'm gobsmacked. I am watching, though. That formula has promise...the v^2 makes intuitive sense.
The answer is 3.14.
D=(0.5)(rho)(v^2)(A)(Cd)
Assume a common Cd of 1.17 for a regular, square, flat plate.
rho=density of water=62.427lb/cu.ft.
v=flow velocity=8.8ft/sec
A=area of plate=1sq.ft.
D=2830 lb-ft/sec^2
-- OR --
Assume a common Cd of 2.1 for a smooth brick.
rho=density of water=62.427lb/cu.ft.
v=flow velocity=8.8ft/sec
A=area of plate=1sq.ft.
D=5080 lb-ft/sec^2
Does that get into the ballpark?
On a related - there is enough energy in the Gulf Stream to meet the new electricity needs of the entire eastern seaboard for years to come. www.energy.gatech.edu/presentations/mhoover.pdf
Well, I'd just hook a heavy duty scale, like those used to weigh Tarpon's to a cable attached to the plate at the four corners. Toss 'er in, record the result :)
Cd = 1.16 (Mech Engr Handbook square plate)
V 8.8 ft/sec
Density = 62.4 lbs/ft^3
g = 32.2 ft/sec^2
F = lbs
V^2= (ft/sec)^2
D = lbs/ft^3
g = ft/sec^2
A = ft^2
F = 174.081272 lbs
It will also depend upon the temperature and make up of the water, all of which influence viscosity - which influences the flow coefficient)
You guys are giving me a headache.
Civil Engineers ping
I'm filling in for Fierce Allegiance, let me know if you would like on or off the list.