Posted on 01/23/2012 8:31:19 AM PST by mvpel
Newt Gingrich can’t be President. Not because of his $1.6 million Freddie Mac scandal, or his fake charity scandal, or his $300,000 ethics fine while Speaker, the arms dealer scandal, or any of his other personal and financial scandals. Newt Gingrich (or Rick Santorum) can’t be President because to be nominated, you need delegates.
...
Newt has lots of media coverage, but in the physical world where campaigns actually occur he can’t get 1141 delegates.
...
No candidates besides Paul and Romney filed in all the states:
VA - no Gingrich or Santorum - 49 delegates
MO - no Gingrich - 52 delegates, non-binding primary
D.C. - no Santorum - 19 delegates
So that's 101 lost for Gingrich, and 68 lost for Santorum.
Then, even when your campaign stops its Aegean cruise long enough to file, you still have to get people to sign up as delegates. Santorum and Gingrich only have partial slates of delegates in IL, OH, and TN, which together represent 193 delegates. They are missing different numbers of delegates, but these losses push Gingrich down to levels where he would have to have landslides in all the remaining states.
...
LOL!!!
This read like it was written by a Paultard.
Delusional.
Well if the Bedford Patch says so, it must be true.........../s
It’s the kind of thinking Medved has been using since Cain to explain why this is Romney’s year.
I believe it was....certainly from Paul’s site.
They keep referencing some notion of 564 delegates, but after questioning the validity of the statement, no legitimate response is ever offered.
Don’t take this wrong, guys. But isn’t this right? Delegates are everything in the end.
Can someone else do the math and prove this analysis to be flawed?
Hogwash.
GO NEWT GO......
Romneybot begone!
However, the race is for which candidate is going to have his rear end handed to him by Newt!
Boy their math is way off. It is still anybody’s game and the few States where some candidates have had problems aren’t enough to risk their position.
So far, we are talking under a hundred delegates lost for most of the candidates out of over 1100 needed. A ‘sweep’ for Newt isn’t even necessary. Just a consistent strong showing can keep him on top.
With lots of winner take all states you don’t need a popular vote landslide to get win a delegate landslide. Heck, even in non-winner-take-all SC Newt ended up with all the delegates, despite winning less than half of the primary voters.
Well, the signs do point to this being a close race for delegates. One thing I would caution is the 132 or so Republican Superdelegates that aren’t bound to primary or caucus results. Right now, NH, SC, and FL got stripped of their voting rights, but in a close race I suspect they would reinstate them letting people like Sununu get a delegate vote.
Also, if Ron Paul accumulates even 150-200 delegates, that, along with the Superdelegates may be enough to stop anyone at the convention from obtaining a majority. It would not surprise me for the Paul people to throw their support to Romney at the convention and it would not surprise me for the Romney people to make a deal with the Paul people to stop Gingrich.
Math is math, and is not subject to delusions. I haven’t run the numbers myself, but I’m sure it’s possible to do so easily.
I actually rather expect that to happen...
It seems to me that Newt is smart enough to figure this delegates issue out better than anyone, and if it were true that he couldnt attain enough delegates, I would think he would drop out rather than put himself thru all the bashing that is going on, and is surely to come. This has got to be an untrue article...
Re: Basic math
1 + 1 = 2
2 + 2 = 4
Please pick it up from here, and pay attention.
I’ll have to find it but I also recall that Paul may have made a mistake in Illinois and may not be on the ballot there.
Disclaimer: Opinions posted on Free Republic are those of the individual posters and do not necessarily represent the opinion of Free Republic or its management. All materials posted herein are protected by copyright law and the exemption for fair use of copyrighted works.