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To: dayglored

“White pigment paint absorbs no visible wavelengths “

Since we are nit-picking ...

The photon excites electrons (is absorbed) and if not in resonance another photon is emitted.

OTOH, no pigment is a perfect reflector.


148 posted on 02/03/2025 10:29:55 PM PST by TexasGator (11'r/11111.111''!11)
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To: TexasGator
You are correct, that you for the clarification.

I was making a somewhat inexact generalization in the service of a much larger, broader point. Nevertheless your nit-pick is appreciated.

150 posted on 02/03/2025 10:36:04 PM PST by dayglored (This is the day which the LORD hath made; we will rejoice and be glad in it. Psalms 118:24)
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To: TexasGator
Now here's one to augment something I wrote earlier. It's not difficult or unsolved, but it's a twist on the prior discussion.

Inline color filters. They aren't exactly reflective per se, since they accept light from a source and pass it forward to the object or sensor. Yet they're subtractive, i.e. when you combine them the output tends to black just like pigments.

All this really says is that "reflective" is not a comprehensive descriptor for the subtractive process. You must also include "pass-through". Any other categorically distinct things come to mind?

155 posted on 02/03/2025 10:48:57 PM PST by dayglored (This is the day which the LORD hath made; we will rejoice and be glad in it. Psalms 118:24)
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