Does not compute.
At the height of the day, the sun sits exactly 45-degrees above the horizon at 45-North.
Higher parallels (by number) move the “mid-day” sun lower in the sky.
This is confirmed bvy the summer solstice in and near the arctic circle, where the sun will never drop below the horizon nor rise above the horizon a few degrees.
Chuckster can attest to that.
Oklahoma City OK is close to 35 North.
There is actually a vitamin D wiki!
https://vitamindwiki.com/Vitamin+D+vs+angle+of+the+sun
I cannot vouch for its accuracy, but I’ll share anyway.
Vote flips in a Republican primary will only strengthen the leftists argument that it is the Republicans who are cheating and that the mid-terms must be delayed while [the party in power] can fix it.
https://freerepublic.com/focus/f-chat/4081064/posts
Still on schedule and within budget.
Directly overhead is 90 degrees to the horizon.
OK. Leaving declination and other complications out of the discussion:
I am at, approximately 57* North Latitude. The highest possible angle of the sun above the horizon on the Summer solstice is 57*.
At the equator, it would be 90* (IOW - 0*, directly over head at noon).
At the poles it would be right on the horizon. (Again, ignoring declination)
Navigation 101.