to split a deuteron costs 2.2 MeV. Hot fusion of two deuterons
yields about 4 MeV. At best this would
never yield more than about a factor of 2....and that’s not taking into account
any of the losses. And those losses will
be very significant.
1) Maybe 1% of the electrons will create significant x-rays, of which only a
fraction will have the requisite minimum
energy of 2.2 MeV. => most of the electron energy ends up as heat.
2) Only a fraction of the 2.2 MeV or greater x-rays will split a deuteron
(1%?). The rest just ionize atoms and end up
as heat.
3) Of the split deuterons, only a fraction will produce neutrons with even the
minimal energy required to fuse two
deuterons (5 keV? - but the more the better).
4) Of those neutrons, only a fraction will actually accelerate a deuteron
resulting in a fusion reaction.
5) A fusion reaction will primarily create two energetic particles, both of
which can further accelerate other
deuterons, however only a tiny fraction of them will actually do so. Most will
simply lose energy ionizing surrounding
atoms, and end up as heat.
In all, …. they would be lucky to get even one part in a million of the
electron beam energy out as fusion energy,
if the proposed method were actually an accurate description of what happens in
their reactor.
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Re: Lattice Confinement Fusion Terry Blanton Wed, 19 Aug 2020 11:43:21 -0700
On Wed, Aug 19, 2020 at 12:39 PM CB Sites wrote:
” Any ideas as to why they chose Erbium for the host metal?”
*** I can think of one reason:
Palladium 2,197.00 USD per Troy Ounce
Platinum 962.50 USD per Troy Ounce
Erbium $650 per kilogram!
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