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To: grey_whiskers
(2700 lbs * 2500 ft/s ) shell * 9 shells = 6.075 x 10**7 ft*lb/s

The mass of the ship is 57,000 tonnes * 2204 lb/tonne =1.25628 x 10**8 lbs

Divide the momentum of the one side (shells), by the mass of the other (ship), to get the initial velocity of the ship:

1.25628 x 10 **8
__________________
6.075 x 10** 7

~= 2.0 ft/sec

Two minor math errors that significantly affect the answer.

The combined momentum of the shells is 6.075x10**5 ft*lb/s vice 6.075x10**7 ft*lb/s.

You reversed the division from your statement. It should be:

6.075 x 10**5
__________________
1.25628 x 10**8

~= 4.849x10-3 ft/sec or ~6 hundredths of an inch.

I submit that this is insignificant when referring to a battleship.

WWG1WGA

Garde la Foi, mes amis! Nous nous sommes les sauveurs de la République! Maintenant et Toujours!
(Keep the Faith, my friends! We are the saviors of the Republic! Now and Forever!)

LonePalm, le Républicain du verre cassé (The Broken Glass Republican)

1,312 posted on 01/09/2020 9:36:46 AM PST by LonePalm (Commander and Chef)

To: LonePalm
Wait till after midnight again, so I can follow my chicken scratch...(was up till 3am on a work project...) Thanks 😀
1,349 posted on 01/09/2020 11:06:48 AM PST by grey_whiskers (The opinions are solely those of the author and are subject to change with out notice.)

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