If we can't believe numbers, why bother with words?
Z
you can use that exact same proof for any two numbers next to each other.... so 2=1; 3=2; 5=4, etc
But yes I get your point.
In case people don`t see it...
3(a+b-c)/(a+b-c)=4(a+b-c)/(a+b-c) reduces to
3(0)/(0)=4(0)/(0)
Since a+b=c hence a+b-c =0
There is a reason they don’t allow division by zero in math class.