To: Red Badger
Put an asteroid in orbit about the earth and it becomes a moon. It's no longer an asteroid.
The geostationary altitude is 36,000 km above the earth. That means an orbital period of 24 hours. If you go to 50,000 km above the earth the orbital period for a circular orbit is about 36 1/2 hours.
If I were a satellite owner I'd be concerned about this cable constantly slicing through the geostationary belt.
48 posted on
03/28/2017 10:16:25 AM PDT by
Purdue77
(I can't afford a tag line.)
To: Purdue77
49 posted on
03/28/2017 10:17:44 AM PDT by
Red Badger
(Ending a sentence with a preposition is nothing to be afraid of........)
To: Purdue77
"The geostationary altitude is 36,000 km above the earth. That means an orbital period of 24 hours. If you go to 50,000 km above the earth the orbital period for a circular orbit is about 36 1/2 hours."
I'm not an astro-physicist, and I don't even dabble. So I'm probably asking a dumb question but isn't mass of the satellite a factor? In other words, the geostationary orbit of something with the mass of X isn't the same as that with the mass of X(1.25). Wouldn't it need more escape velocity to remain in orbit?
50 posted on
03/28/2017 10:21:22 AM PDT by
z3n
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