[NoCmpromiz]

As a refresher, you posted this link...

C/2012 S1 (ISON) Orbit Diagram ( Current )

I'm not sure what exactly it was that you were tryuing to enlighten us with, but just so you know, after sifting through that web page from JPL, the vital information you really need is at the bottom.

Since you might not be able to extract that information, I have done it for you:

Close-Approach Data
2013-Dec-26 20:23
Time Uncertainty - (days_HH:MM) 00:12
Body Earth
Nominal Distance (AU) 0.430597325537957
Minimum Distance (AU) 0.430298254046287
Maximum Distance (AU) 0.430896449411539
V-relative (km/s) 47.5108311739296
V-infinity (km/s) 47.5107009325476
Time Uncertainty (minutes) 11.6325082661853

It is left to you to do the math and discover what 0.430298254046287 AU is in miles (or km if you prefer to function in metric..)

Or you can accept my quick off-the-top-of-the-head-estimate of about 37 MILLION miles.

All from data on a page you linked us to.

You're welcome.

[Yosemitest]

Read comment #329.

Mostly I wanted to know how much "SPREAD" Ison's fragments would need to be a danger to Earth.
Your "quick off-the-top-of-the-head-estimate of about 37 MILLION miles" is what I thought, too.
Now how much of an angle from the back side of the Sun or before the backside of the Sun, during Isons breakup, would that distance require in the scattering of the "V" debris ?

But I haven't had time to work on it, yet.