I described this exact same model a few years back here but it was rejected by some of the hard core eggheads.
If we put 100 pennies in a bag and dump them out, the odds are very, very slim we get 50-50.
Say we get 42-48. The 42 antimatters neutralize 42 of the matters, dumping out a huge amount of energy (and mass itself in the form of neutrinos), and leaves 6 of the original 100 that are detectable.
I’m not sure what the average of the deviation from 50-50 would be, but if that expected average matches whatever observables there are, then people ought to give it some serious consideration.
And my bad... 42 and 48 is 90. I meant 52-48.
Same principle.
You owe me a dime.
I’m not sure what the average of the deviation from 50-50 would be,
In N independent trials of an experiment with a probability of success (heads) equal to p, the average number of successes would be p*N and the variance would be p*(1-p)*N. (Standard deviation sqrt(p*(1-p)*N))). In a hundred trials with a fair coin, the mean would be 50, and the standard deviation would be 5. About two thirds of the time, you would expect to get between 45 and 55 heads (or tails.)
As the number of trials grows arbitrarily large the distribution approaches a normal distribution (DeMoivre-LaPlace theorem, a special case of the central limit theorem.) For most purposes, one can make practial predictions about likelihoods of outcomes by assuming the population conforms to a normal distribution, but care needs to be taken for tail probabilities. See the binomial distribution for all the gory details.
The ratio of to the standard deviation to the mean decreases as 1/sqrt(N), regardless of p, for p not equal to zero or one. (In which cases, the std. dev. is zero.)
I think your analogy to a bag of pennies is a good one. Alan Guth believes that the actual ratio ended up something like 51-49, which would mean that all the galaxies we see, and all the dark matter we think is there, represents something like 2% of the original mass at the time of the Big Bang.