Free Republic
Browse · Search
News/Activism
Topics · Post Article

To: DuncanWaring

“I double-checked the math myself, and got an answer I don’t trust, but it may be correct if all 830 million wind turbines run at full power non-stop.”

Please check my math!

I verified that his number (25 billion mwhs) would be for a year. That is 25x10^9 mwhs.


One turbine at ‘max’ for a year:

3 x 24 x 365 = 13,000 mwhs.

At 20% efficiency = 2,600 mwhs.

For 830x10^6 turbines:

2.6x10^3 x 830x10^6 = 2,158 x 10^9 = 21 x 10^11 mwhs.



22 posted on 08/12/2017 8:16:35 AM PDT by TexasGator
[ Post Reply | Private Reply | To 19 | View Replies ]


To: TexasGator

One turbine running at 100% for the full year would produce 3 x 24 x 7 MWH per year: 26280 MWH.

Divide that into 25 billion MWH: 951000 wind turbines running full-time full power.

Divide that 951000 by whatever efficiency you want to get the number of turbines necessary to produce the 25 billion MWH at that efficiency.


39 posted on 08/13/2017 5:04:44 AM PDT by DuncanWaring (The Lord uses the good ones; the bad ones use the Lord.)
[ Post Reply | Private Reply | To 22 | View Replies ]

Free Republic
Browse · Search
News/Activism
Topics · Post Article


FreeRepublic, LLC, PO BOX 9771, FRESNO, CA 93794
FreeRepublic.com is powered by software copyright 2000-2008 John Robinson