“Whether its a vacuum or full of argon, its still a 60W bulb. All 60W is losses, therefore heat. Where do you think that heat is going?”
Your wrong... Maybe your not thinking this through, or maybe you don’t have the background. I don’t know...
If you can maintain the temperature of the tungsten fulfillment without loosing as much heat to the atmosphere, then you can get the same light output without using 60W.
Same as with an electric water heater. Remove the insulation and you will use more power for the same temperature water.
So if I dip the glass part in a large bowl of water; it will get dimmer; right?