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To: GLDNGUN

>>Ninety-six percent (96%) of Badger State voters say they are sure to vote in this election. Romney leads 51% to 47% among these voters. <<

This has got to be wrong as written. First, it’s hard to believe that 96% of registered voters will vote. That would be a huge turnout.

Second, 96% is essentially everyone in the poll, and if the 96% are splitting 51/47, how does the overall polling result get down to a tie? Not possible mathematically.

I’m guessing that the statement has a misprint on the percentage sure to vote. It would make sense if it said 46% said they are certain to vote and Romney leads 51/47 in that group, or any other percentage between 40% and 60%, but the 96% number is clearly impossible.


21 posted on 10/26/2012 12:43:18 PM PDT by Norseman (Defund the Left-Completely!)
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To: Norseman

“This has got to be wrong as written. First, it’s hard to believe that 96% of registered voters will vote. That would be a huge turnout.”

It just means that 96% of Rasmussen’s sample say they are certain to vote. Rasmussen’s sample isn’t just a scattershot cross-section of people. He deliberately focuses on prime, engaged voters.


24 posted on 10/26/2012 1:23:31 PM PDT by Kingosaurus
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To: Norseman

Two reasons they may have gotten this number: It’s extrapolated from a relatively smallish sample, and it’s the answer people like to give about themselves and doesn’t necessarily mean they will vote.


25 posted on 10/26/2012 1:30:23 PM PDT by firebrand (Beware of wishful thinking--the mousetrap of small minds.)
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