[Iron Munro]

That’s quite a tecnological advance.

Now on to the next challenge:

How to slow down to a stop from 50,000 mph without turning the humans into grease spots on the bulkhead.

[Darth Reardon]

Start braking a little over half way there?

But yeah, my first thought was how many G’s would it take.

[Jewbacca]

“How to slow down to a stop from 50,000 mph without turning the humans into grease spots on the bulkhead.”

Accellerate at 1g half way there and decellerate 1 g half way back (or whatever the ratio is), minus whatever speed is needed to maintain stable orbit at Amrs.

[Jewbacca]

how long does it take to travel 64,000,000 in a ship capable of accelerating at 1g assuming the maximum acceleration is used, then:

1g = 32 ft / s^2

1g = (32 ft /s^2)(3600^2 s^2/hr^2)(1 mile/5280 ft)

1g = 78545 mile/hr^2

64,000,000 = 2 * 32,000,000 (because you spend half the time accelerating and half the time decelerating - otherwise you get there, but you can’t stop)

d = at^2
t = sqrt(d/a)

t = sqrt(32,000,000 miles / (78545 miles/hr^2))
t = sqrt(407)
t = 20.2 hr

Double that and get 40.4 hr, or just under two days.