To: sonofstrangelove
How do you dissipate 7.2 trillion degrees?
18 posted on
02/16/2010 1:54:55 PM PST by
TalBlack
To: TalBlack
My guess is through the Laws of Thermodynamics
25 posted on
02/16/2010 2:03:25 PM PST by
ErnstStavroBlofeld
("I have learned to use the word "impossible" with the greatest caution."-Dr.Wernher Von Braun)
To: TalBlack
How do you dissipate 7.2 trillion degrees? The amount of mass involved was miniscule, the specific heat of a gluon quark mixture is a little hard to calculate (I'm not sure how many degrees of freedom are involved) but if we assume it's about the same as the original nucleus, one mole of gold is 6 x 10^23 atoms ~ 200 grams, so there was enough energy to raise the temperature of 200 grams, about half a pound, of gold, by about 10^-11 degrees (7.2 x 10^12 / 6 x 10^23) Celcius. Approximately equal to the amount of CO2 induced global warming since 1900.
28 posted on
02/16/2010 2:31:58 PM PST by
Lonesome in Massachussets
(The naked casuistry of the high priests of Warmism would make a Jesuit blush.)
To: TalBlack
How do you dissipate 7.2 trillion degrees?
With one big-ass fan.
29 posted on
02/16/2010 2:33:42 PM PST by
reagan_fanatic
(The liberals are asking us to give Obama more time. Is 25 to life enough?)
To: TalBlack
Since it is only in an area smaller than an atomic nucleus, all you have to do is wait a microsecond. Light flies out in all directions carrying away the energy.
31 posted on
02/16/2010 2:44:47 PM PST by
JasonC
To: TalBlack
How do you dissipate 7.2 trillion degrees?
Quite quickly if the surface area is significant compared to the volume, as it would be in this case.
75 posted on
02/17/2010 3:27:14 AM PST by
altair
(US Passport holder working LEGALLY in India)
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