A new superconducting state of matter at room temperatureIs this an attempt to revive the diamond industry?
To: *tech_index; Sparta; freedom9; martin_fierro; PatriotGames; Mathlete; fjsva; grundle; beckett; ...
2 posted on
04/16/2003 5:02:16 PM PDT by
Ernest_at_the_Beach
(Where is Saddam? and where is Tom Daschle?)
To: Ernest_at_the_Beach
let me know when they start buying kidney stones for superconductors
3 posted on
04/16/2003 5:06:09 PM PDT by
joesnuffy
(Moderate Islam Is For Dilettantes)
To: Ernest_at_the_Beach
For it to be workable, it would need to be a synthetic diamond layer on some substrate. You need to have the actual superconductor be long enough to actually be useful.
4 posted on
04/16/2003 5:07:07 PM PDT by
SauronOfMordor
(Heavily armed, easily bored, and off my medication)
To: Ernest_at_the_Beach
what a waste of good jewelery ; )
5 posted on
04/16/2003 5:08:11 PM PDT by
xsmommy
To: Ernest_at_the_Beach
Remember Texas A&M published room temp super conductivity.
Their measurements were off.
When another person can duplicate this, it will make more
sense.
To: Ernest_at_the_Beach
Electron transition efficiency on diamond surfaces has been studied for decades... Even before Hagstrum's seminal work on bombardment-induced Auger transitions... Looks like promising stuff...
12 posted on
04/16/2003 6:04:26 PM PDT by
maxwell
(Well I'm sure I'd feel much worse if I weren't under such heavy sedation...)
To: Ernest_at_the_Beach
Science: Can diamond now be a superconductor?It's been known by men, for thousands of years, that a diamond is a superconductor to the bedroom.
The larger, the more conductive.
To: Ernest_at_the_Beach
Half a milliamp at 1000V through a diamond sounds more like a very expensive 2 megaohm resistor than a superconductor.
To: Ernest_at_the_Beach
Is this an attempt to revive the diamond industry? Now you have a friend in the diamond business.
Can you imagine how much more annoying this guy's commercials could get?
To: Ernest_at_the_Beach
I assume these diamonds would have to be manufactured in order to infuse them with the necessary oxygen ion content?
18 posted on
04/16/2003 6:31:00 PM PDT by
semaj
To: Ernest_at_the_Beach; Jack of all Trades
" the density of electrons in this layer reaches a critical value at which a Bose-Einstein-type condensate of electron pairs forms.Why should electrons with spin of +-1/2 pair up to essentially form a particle with spin zero and a charge of -2? Where's the driving force? They're both negatively charged, the repulsive force is significant and pairing these fermi particles in this gas involves a higher energy state.
Current continues to flow from the diamond cathode through this layer to the anode, even though there is no voltage across the layer - a sign of superconductivity.
The diamond is acting like a leaky dielectric here. The only reason there is emission from the surface of the diamond is, because the potential of the gold electrode, the anode, is different from that at the surface of the diamond. The field between that surface will be low, because most of it is across the diamond, but it's still there. All that's being observed here is that the mean free path of the electrons in any other direction than the field is much larger than the gap. ie. The electrons don't bump into each other, or into anything else, on the way to the gold plate. Low density electrons, flying though a vacuum, is not a superconducting system.
Also the gap can't be at the same potential as the gold. The gold is positive and the gap is less positive, by there respective makeups and geometry.
It's an expensive 2Mohm resistor.
23 posted on
04/16/2003 7:53:35 PM PDT by
spunkets
To: Ernest_at_the_Beach
BTFL
34 posted on
04/17/2003 9:54:00 AM PDT by
techcor
To: Ernest_at_the_Beach
Ah yes...
The advent of the Dilithium crystal.
Damn it Jim
36 posted on
04/17/2003 1:31:22 PM PDT by
pray boy
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