When an electron has velocity the total electric field increases over that of a stationary electron.No, it doesn't. That would violate Gauss's Law.
I don't see how the uncertainty principle applies, especially to a field.
Suppose you have an electron in orbit around a nucleus. The HUP states that the uncertainty in energy times the uncertainty in time is greater than some calculable fraction of Planck's constant. If the electron were to continue to radiate energy, its orbit would continually shrink (resulting in a shorter period), and its energy would continually decrease. At some point, the product of these quantities will fall below the stated inequality, which is forbidden. There must therefore be a ground state past which the orbiting electron cannot radiate.
The Earth in its orbit is about 75 orders of magnitude away from this limitation.
If Cavendish could measure g with small lead spheres over 100 years ago, certainly today's physicists could produce gravity waves on the orders of tens of kilohertz and measure them.
Describe how to do it. It's easily worth a Nobel Prize.
Also as the frequency of the wave increases so would its radiated intensity, making the measurement very easy.
That doesn't make sense.
Wouldn't gravity waves cause an effect similar to the Lorentz contraction and hence could never be measured?
The Lorentz contraction can be measured.
1. You're right the electric field doesn't increase. Also mass does not increase with velocity either. I forgot about the time derivitives and retardation in Gauss's law.
2. Excellent analogy! What is the charge of the earth and what is the charge of the sun? Do the retarded potentials scale likewise?
3. Easy. Take two lead spheres, each on the end of a single rod. Rotate radially about the center of mass, just like two equal mass planets orbiting about each other (kind of like a Woodward governor). The scale is smaller than planets but the rotation rate is much higher. The gravity signal would be of a frequency much higher than the background noise. To show it is a gravity wave, measure signal intensity as a function of distance. I think I can find some references on this, I'll send them to you if I do.
4. Higher acceleration = higher radiation intensity. Higher acceleration = higher rotation rate. Therefore, higher rotation rate (frequency) = higher radiation intensity.
5. Please cite the experiments showing that the Lorentz contraction can be measured.
It may be very helpful for you to review freshman E&M. Gauss's law applies to electrostatics, not moving charge. Apply Gauss's law to a current carrying wire. The integral of E over the cylindrical volume is zero, is it not? That means there's no net charge enclosed, as is true in an electrically neutral conductor. Yet the measured E field is in the direction of the current travel is it not? E is in the direction of the current density. The wire has a net E field, but net zero charge. Where would this net E field come from if the total electrostatic charge of the wire is zero? Why does it exist only when the charge is moving? Please don't invoke exotic quantum theories to explain this, do it as Einstein would with simple understandable English.