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What is the square root of pi?
Me ^

Posted on 12/08/2001 2:26:08 PM PST by ambrose

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To: Lazamataz
Ouch. My brain hurts.
221 posted on 12/08/2001 8:56:25 PM PST by clikker
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To: MitchellC
You forgot to carry the 1.

I always carry one.

A beer or a gun.

222 posted on 12/08/2001 8:58:44 PM PST by Lazamataz
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To: Lazamataz
Yeah, well maybe there is an integer in the cheese between 0 and 1 and we just haven't discovered it yet and won't until somebody cuts the cheese.
223 posted on 12/08/2001 9:00:03 PM PST by RightWhale
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To: WileyCoyote22
Where does infinity end ?

Just before infinity + 1. :)
224 posted on 12/08/2001 9:04:27 PM PST by al-andalus
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To: Bill Rice
That's because your computer probably rounded them both to about 4 or 5 places when you "checked" it. I don't think they take it any further.

No, I specifically used Rexx where I can set the numeric digits to any significance I want. I had the Pi program already, and I just fed the answer to the SQRT function that is a part of the PI program. I have compared the output to published lists of Pi digits, and it is accurate. I think that the differences beyond 1000 digits of Pi are too small to show up in the calculation of the square root at that point.

Here is the program:

/* Square root of Pi to digits places/2 */
parse arg places
numeric digits places /* Number of places for PI calculation */
number_pi=PI(places)
sroot=sqrt(number_pi,places/2) /* half the number for the square root */
lineout("sroot.txt",sroot) /* Output to file for cutting and pasting */
exit

PI: procedure
parse arg P
if P = "" then P = 9; P=P+3; numeric digits P
X = SQRT(2, P); Pi = 2 + X; Y = SQRT(X, P); X = Y
do forever
X = 0.5 * (X + 1 / X)
NewPi = Pi * (X + 1) / (Y + 1)
if Pi = NewPi then return trunc(Pi,P-3)
Pi = NewPi
X = SQRT(X, P)
Y = (Y * X + 1 / X) / (Y + 1)
end

SQRT: procedure
parse arg N, P
if P = "" then P = 9; numeric digits P
parse value FORMAT(N,,,,0) with N "E" Exp
if Exp = "" then Exp = 0
if (Exp // 2) <> 0 then
if Exp > 0 then do; N = N * 10; Exp = Exp - 1; end
else do; N = N / 10; Exp = Exp + 1; end
X = 0.5 * (N + 1)
do forever
NewX = 0.5 * (X + N / X)
if X = NewX then return X * 10 ** (Exp % 2)
X = NewX
end

225 posted on 12/08/2001 9:08:04 PM PST by Excuse_Me
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To: ambrose
Cubed potatoes in chicken stock, with some flower and peas, baked between two crusts at 450 °F for about an hour. They're good after a cold afternoon on the back forty.
226 posted on 12/08/2001 9:10:38 PM PST by Carry_Okie
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To: Lazamataz
Laz, if you think about how pi is derived, what it represents as a ratio between the radius of a circle and the circumference, then the value of pi will vary according to the strength of the garvitational field in which the ratio is measured. [I learned that from Dick Feynman. He wasn't lyin' to me, was he?]
227 posted on 12/08/2001 9:13:14 PM PST by MHGinTN
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garvitational = gravitational (in some universes)
228 posted on 12/08/2001 9:15:10 PM PST by MHGinTN
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To: lowbridge
What kind of pi? Apple pi? Pizza pi?

In Wisconsin, it's called a Cow Pi.

Or if you're really in to it...it's called cow tippn'.

229 posted on 12/08/2001 9:20:05 PM PST by MotleyGirl70
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To: MHGinTN
It's an interesting concept but the effect should only be observed by someone outside of the gravitational effect. To the person inside the gravitational effect the circumfrence and the radius will not vary.
230 posted on 12/08/2001 9:20:49 PM PST by Lazamataz
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To: Tennessee_Bob
Roblochon is the first cheese of Savoy

Are we allowed to bomb France during Roblochon?

231 posted on 12/08/2001 9:23:03 PM PST by Silly
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To: LibKill
While we are at it, what is the square root of negative 1?

that would be i.

232 posted on 12/08/2001 9:25:00 PM PST by sten
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To: BADJOE
There is no square root of any negative number.

The square root of -1 is i, and the square root of any negative number is simply i* the square root of the absolute value of the number that you are taking the square root of.

233 posted on 12/08/2001 9:25:11 PM PST by L_Von_Mises
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To: is_is
oh me....oh my....i love pi....

Not a big fan of pi...but I love grits.

234 posted on 12/08/2001 9:25:29 PM PST by MotleyGirl70
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To: AmishDude
New movie out: "Silence of the Pi".
235 posted on 12/08/2001 9:30:48 PM PST by MotleyGirl70
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To: Excuse_Me
Kewl! Back in the late 80's, my guru was called into a company who had just spent 6 figures on an expensive measuring device that was giving them fits. They made bearings or something.

It was supposed to log a bunch of measurements, do Chi-square stuff, and then tell them when it was time to retool.

It was taking and logging the measurements to 6 places, but then they were turning out big batches of rejects - and it wasn't ever popping up any flags to retool.

He determined that while the actual measuring device was accurate and functioning, the cheeseball computer (Probably a 286), that came with it was rounding all those super precise numbers, and then butchering up the math with even more rounding in the statistical analysis process.

He ended up selling them a clone system, and writing them a program that did something like you did to keep the extra places.

236 posted on 12/08/2001 9:34:26 PM PST by Bill Rice
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To: ThomasPaine2000
"Pi" equals the length of Barbara Streisand's nose. Right?
237 posted on 12/08/2001 9:36:40 PM PST by MotleyGirl70
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To: Lazamataz
It's an interesting concept but the effect should only be observed by someone outside of the gravitational effect. To the person inside the gravitational effect the circumfrence and the radius will not vary.

Wait, is this just the beginning of a clever excuse to shoot the Dems into space for 'research purposes'? :)

(If not, darn.)

238 posted on 12/08/2001 9:45:19 PM PST by MitchellC
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To: Lazamataz
It would be an interesting thought experiment to conjecture how the universe expressed spatial dimensional component and thus separated linear, planar, and volumetric expression such that pi could be an expression in planar and volumetric space, but not in linear space. ... pi had an origin! [I like chocolate cream pi and banana cream pi ... 'e' 'e' here's the leftovers]
239 posted on 12/08/2001 9:48:54 PM PST by MHGinTN
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To: Lazamataz
BTW, that the value of pi would be on a sliding scale in the neighborhood of the event horizon of a black hole has been basis of one of my arguments with Hawking. "To the person inside the gravitational effect the circumference and the radius will not vary." Actually, when approaching a great-enough differential of gravitational force, since time is altered also, the changes to pi amount to temporal shift rather than spatial.
240 posted on 12/08/2001 9:52:48 PM PST by MHGinTN
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